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love history [14]
2 years ago
11

Two functions are graphed on the coordinate plane.

Mathematics
1 answer:
rosijanka [135]2 years ago
7 0

Answer:

Option B

Step-by-step explanation:

We can see that, from the picture provided, the graphs intersect at points( 0, 4 ) and ( - 4, 4 ), respective to functions f( x ) and g( x ). These intersection points makes each function equivalent to one another, and hence -

Function f( x ) where x = - 4 / Function g( x ) where x = - 4,

f( - 4 ) = 4,\\g( - 4 ) = 4\\----------\\f ( - 4 ) = g ( - 4 )

Respectively function f( x ) where x = 0 / Function g( x ) where x = 0,

f( 0 ) = 4,\\g( 0 ) = 4\\----------\\f ( 0 ) = g ( 0 )

<u><em>Your solution should be option b, "  f(-4) = g(-4) and f(0) = g(0) "</em></u>

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3:1 is your answer bruuuuuuhhhh

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Suppose that you can only use the set of small letters characters (a-z) and odd numbers (1, 3, 5, 7, 9) to set a password. What
Flauer [41]

Answer:

31^8

Step-by-step explanation:

To create a password, you need to select 8 characters (not necessarily different) from the set {1,3,5,7,9,a,b,c,...,z}. Now, this set has 31 elements: the 26 lowercase letters from the alphabet and the 5 odd numbers (1,3,5,7,9).

Now, there are 31 ways to choose the first character, it can be any element from our set. The second character can also be chosen in 31 ways, because there are not restrictions (repetitions, specific characters, etc). Similarly, the third, fourth, fifth, sixth, seventh and eighth characters have 31 possibilities each one.

The number of passwords is the number of ways of selecting the 8 characters, then by the multiplication principle the number of passwords is 31×31×31×31×31×31×31×31=31^8.

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NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

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We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

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Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

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Then:

c  = 2d = 2*(-1) = -2

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So the values are:

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If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

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Answer:

x=-4/3

Step-by-step explanation:

x -4x-1=3

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I hope this helps!

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The answers please. Don’t know how to do #1
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Your correct. It is what you put down
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