What is 9c-c equal when u combined like terms?
8c
Answer:
C
Step-by-step explanation:
Here in this question , we are interested in calculating the total distance covered by the train in the 10 minutes that it ran.
From the first part of the question, we already know the distances in the first 5 minutes.
Now, to calculate the total distance in the second 5 minutes, we use the distance formula since we have the average speed and the time;
Mathematically; Total distance = average speed * time
From the question, average speed is 33km/h, while time is 5 minutes. To achieve a consistent unit, we convert 5 minutes to hours.
That would be 5/60 = 1/12 hours
So the total distance in the second 5 minutes is;
33 * 1/12 = 2.75 km
Now, to calculate the total distance traveled, let’s add up the distances in the first 5 minutes and convert to kilometers;
That would be;
68 + 127 + 208 + 312 + 535 = 1,250 m
Let’s convert this to km.
We simply divide by 1000 = 1250/1000 = 1.25 km
The total distance is thus ;
1.25 + 2.75 = 4 km
The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π
<h3>The circle with center P</h3>
Given that the circle has a center P
It means that lengths PQ, PR, PS and PT
From the question, we understand that QR = ST.
This implies that triangles QRP and STP are congruent.
i.e. △QRP ≅ △STP is true
<h3>The length of the minor arc</h3>
The given parameters are:
Angle, Ф = 99
Radius, r = 1
The length of the arc is:
L = Ф/360 * 2πr
So, we have:
L = 99/360 * 2π * 1
Evaluate
L = 198/360π
Divide
L = 11/20π
Hence, the length of the minor arc is 11/20π
Read more about circle and arcs at:
brainly.com/question/3652658
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Answer:
The probability that the household has only cell phones and has high-speed Internet is 0.408
Step-by-step explanation:
Let A be the event that represents U.S. households has only cell phones
Let B be the event that represents U.S. households have high-speed Internet.
We are given that 51% of U.S. households has only cell phones
P(A)=0.51
We are given that 70% of the U.S. households have high-speed Internet.
P(B)=0.7
We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.
P(B|A)=0.8
Hence the probability that the household has only cell phones and has high-speed Internet is 0.408
