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Tomtit [17]
3 years ago
9

Which could be the side length of a 30°-60°-90° triangle?

Mathematics
1 answer:
pshichka [43]3 years ago
5 0
I believe the answer is C
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What is the reduce form of 10/ab+x
madam [21]

1.

\frac{10}{2 {ab}^{2} }  \times   \frac{ {a}^{2}  {b}^{2}}{5}

=  \frac{5}{2a {b}^{2} }  \times   {a}^{2}  {b}^{2}

=  \frac{5}{2a}  \times  {a}^{2}

=  \frac{5 {a}^{2} }{2a}

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2 years ago
You pick a card at random.
Paha777 [63]
Wouldn't it be 25 percent? 4 cards at a random chance, 100%/ 4= 25%.
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3 years ago
A football stadium will hold 965 students. The cost for a football ticket Is $13 . If a football game is sold out, how much mone
Mekhanik [1.2K]
13×965= $12,545
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7 0
3 years ago
100,000^1/5 x a + 1,000,000^1/2 x a
frez [133]

Answer:

1010a

Step-by-step explanation:

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For example;

100,000^1/5

= 5 x√((100,000) = 10

Likewise;

1,000,000^1/2 = √(1,000,000) = 1000

Thus, we have it that;

10 * a + 1000 * a

= 10a + 1000a = a(1000 + 10) = 1010a

4 0
2 years ago
Please help! Area of part of a circle!!!
Helga [31]

The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².

The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines

b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°)   ⇒   b = 96√3 cm

Call b the base of this triangle.

The vertex angle is 120°, so the other two angles have measure θ such that

120° + 2θ = 180°

since the interior angles of any triangle sum to 180°. Solve for θ :

2θ = 60°

θ = 30°

Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find

tan(30°) = h / (b/2)   ⇒   h = 48 cm

Then the area of the triangle is

1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²

and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:

3072π cm² - 2304√3 cm² ≈ 5660.3 cm²

7 0
2 years ago
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