I really tried but I cant get it
Answer:
5/36 ; 1/12 ; 2/9 ; yes
Step-by-step explanation:
Given the following :
Roll of two fair dice : green and red
Probability = (number of required outcomes / number of total possible outcomes)
(a) What is the probability of getting a sum of 6?
Number of required outcomes = 5
P(sum of 6) = 5/36
b.) What is the probability of getting a sum of 10?
Number of required outcomes = 3
P(sum of 10) = 3 / 36 = 1/12
c.) What is the probability of getting a sum of 6 or 10?
P(getting a sum of 6) + P(getting a sum of 10)
(5/36) + (1/12) = (5 + 3) / 36
= 8/36 = 2/9
The events are mutually exclusive because each event cannot occur at the same time.
Answer:
18
Step-by-step explanation:
7, 17, 27, 37, 47, 57, 67
70, 71, 72, 73, 74, 75, 76, 77, 78, 79
H = hrs she worked
p = phone calls she answered
h x 10 + p x .25 = maggies earnings
Part A
h x 10 + 60 x .25 = 115
Part B
h x 10 + 15 = 115 (multiplied 60 x .25)
h x10 = 100 (subtracted 15 from each side of the equation)
h = 10 (divided 10 into each side)
Part C
10 hrs
Hope this helps