2.8332 rounded to the nearest thousand

pychu [463]

<span>3x</span>² <span>- 8x -3 = 3x</span>² - 9x + x - 3 =

= 3x² - 9x + x - 3 = 3x* ( x - 3) + 1* (x - 3) =

= 3x * (x - 3) + 1 * (x - 3) = (3x + 1) (x - 3)

Answer (3x + 1) (x - 3)

3 0

3 years ago

Read 2 more answers

First the store raised the price of a pot by 20%. Then they announced a 20% discount on the pot. Is the customer going to pay mo

andrezito [222]

Answer:

less

Step-by-step explanation:

An increase of 20% makes the price 120% of the original price.

A discount of 20% makes the discounted price 80% of the previous price.

Original price: x

20% increase in price: 1.2 * x

20% discount over the raised price: 0.8 * 1.2 * x

Now we multiply the numbers in the last expression and compare the result with x.

0.8 * 1.2 * x = 0.96x

0.96 is less than x, so the customer pays less than the original price.

7 0

2 years ago

boeing plans to increase its price for jetliners. with a selling price $201.5 million and a cost of $190.1 million, what was the

scoray [572]

so from 190.1 to 201.5 is 201.5 - 190.1 = 11.4.

now, if we take 190.1 as the 100%, what is 11.4 off of it in percentage?

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 190.1&100\\ 11.4&x \end{array}\implies \cfrac{190.1}{11.4}=\cfrac{100}{x}\implies 190.1x=1140 \\\\\\ x=\cfrac{1140}{190.1}\implies x\approx 5.99684$

3 0

3 years ago

Read 2 more answers

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$