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kati45 [8]
3 years ago
8

Can someone pls help me . Thank you .

Mathematics
1 answer:
Pavel [41]3 years ago
5 0
Answer:
1). 24
2). 8

Explanation:
1).

285$ - 45$ = 240$
240$/10 = 24$

Therefore, he pays 24$ a month.

2).
Let x be the number than triple:

3x - 5 = 19
3x = 19 + 5
3x = 24
x = 24/3
x = 8
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Please help me with this question??m
Keith_Richards [23]

Answer:

75

Step-by-step explanation:

f(1) = 7

f(n) = 3f(n-1) + 3

So what you are trying to do here is find the recursive value (that's what it is called) for f(n). Computers love this sort of thing, but we humans have to do it slowly and carefully.

So let's try f(2)

That means that f(2) = 3*f(n-1) + 3

but if f(2) is used it means that you have to know f(2-1) which is just f(1) and we know that.

so f(2) = 3*f(1)+3

f(2) = 3*7 + 3

f(2) = 21 + 3

f(2) = 24

Now do it again. We now know F(2), so we should be able to find f(3)

f(3) = 3*f(3 - 1) + 3  

f(3) = 3*f(2) + 3      We know that f(2) = 24

f(3) = 3* 24 + 3

f(3) = 72 + 3

f(3) = 75

7 0
2 years ago
It rained 40% of the days during Casey's vacation. What fraction of the days did it rain? Please help me!
Virty [35]
Answer:
40/100=2/5
2/5 is the answer.
6 0
3 years ago
What is -7q-5 (9q-6) -52q+30
Dovator [93]
Hope This helps you..!!

6 0
3 years ago
Solve the following multi-step equation [write the numbers only] Will mark as brainliest if you answer this question
lapo4ka [179]

Answer:

14

Step-by-step explanation:

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2x=28

x=14

8 0
3 years ago
Read 2 more answers
Over the last three evenings, Donna received a total of 129 phone calls at the call center. The third evening, she received 3 ti
lakkis [162]

Answer:

Number of calls received in 1st evening = 24

Number of calls received in 2nd evening = 33

Number of calls received in 3rd evening = 72

Step-by-step explanation:

Let

number of calls received in first evening be "x"

number of calls received in 2nd evening be "y"

number of calls received in 3rd evening be "z"

Total, in 3 evenings, we have 129 phone calls, so we can write:

x + y + z = 129

3rd evening, 3 times as first evening. We can write:

z = 3x

2nd evening, 9 MORE THAN FIRST. So we can write:

y = 9 + x

Now we replace 2nd and 3rd equation in 1st equation to get:

x + y + z = 129

x + 9 + x + 3x = 129

Now, first, we solve for x:

x + 9 + x + 3x = 129\\5x+9=129\\5x=120\\x=24

Solving for y:

y = 9 + x

y = 9 + 24

y = 33

Solving for z:

z = 3x

z = 3(24)

z = 72

Thus,

Number of calls received in 1st evening = 24

Number of calls received in 2nd evening = 33

Number of calls received in 3rd evening = 72

5 0
3 years ago
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