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Alona [7]
3 years ago
5

15-[4-3(2-4)] What is the answer

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0

Answer:

5

Step-by-step explanation:

1. 15-[4-3*(-2)]

2.15-[4+6]

3.15-10

4.5

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If a line crosses though (5,-3) and (-1,6);what is the y-intercept?
harina [27]
(5,-3) (-1,6)
y=mx+b

calculate m:
(-3-6)/(5-(-1)
=-9/6=-1.5

y=-1.5x+b

insert the (5, -3) point to calculate b:

-3=-1.5*5+b
-3=-7.5+b
4.5=b

b=the y intercept, so the line intercepts x=0 at y=4.5
6 0
3 years ago
544ml^2 is how many liters<br><br>show your work
ivolga24 [154]

Answer:

295.936

Step-by-step explanation:

First find out what 544^2 is.  That is 295,936.  There are 100 ml in 1 liter.  So divide 295,936 by 100 to see how many liters are in 295,936 ml.  

295,936÷100=295.936

7 0
3 years ago
4qu, when q= 5 and u = 7
professor190 [17]

Answer:

140

Step-by-step explanation:

Substitute q = 5 and u = 7 into the expression

4qu

= 4 × 5 × 7 = 20 × 7 = 140

4 0
3 years ago
Read 2 more answers
The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar
Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, H_0 : \mu \leq  3.5%

    ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, H_0 : \mu \leq  3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, H_1 : \mu > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

                T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where,  \bar X = sample mean debt ratio of Ohio banks = 6%

             s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} } = 1.83%

             n = sample of banks = 7

So, test statistics = \frac{6-3.5}{\frac{1.83}{\sqrt{7} } }  ~ t_6

                             = 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0
3 years ago
SOMEONE HELP PLEASEE I WILL GIVE U BRAINLIEST IF U ANSWER CORRECT
Vesnalui [34]

Answer:

Im pretty sure its C

Step-by-step explanation:

desmos

3 0
2 years ago
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