Answer:
Domain {-2,0,2}
Range {-2,0,2}
Relation is a Function
Step-by-step explanation:
We are given a relation:
{ (-2,-2) , (0,0) , (2,2) }
Domain can be defined as the all possible values of x for a relation. It is considered as a set of all first values of the ordered pairs of a given relation.
Domain of the given relation is {-2,0,2}
Range can be defined as all possible value of y which corresponds to the values of x in the domain. It is considered as a set of all second values of the ordered pairs of a given relation.
Range of the given relation is {-2,0,2}
A relation is a function if only there is one value of y for each value of x. If in the set of ordered pair of the relation, the value of x gets repeated, then the relation is not a function.
As no values of x are getting repeated, the relation is a function.
Answer:
29520728184915396206153835295
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible
rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
![\sqrt[3]{80}=2\sqrt[3]{10}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D2%5Csqrt%5B3%5D%7B10%7D)
Answer:
-11/8
Step-by-step explanation:
-7/8 - 1/2 = -11/8
