Explain how to compare 0.7 and 5/8.

1 answer:

7 0

You divide 5/8 the answer I get I will look for the largest number:5÷8=0.625 then I compare your answer is 0.7,0.yet.

Hope it helped u

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The circumference of circle 1 is 16 pi units. The circumference of circle 2 is 6 pi units. Which of the following is true about

Yanka [14]

Answer:

Area of Circle 1=>64(pi) units^2

Area of Circle 2=>9(pi) units^2

Step-by-step explanation:

Circumference=2(pi)r

Circle 1: 2(pi)r=16(pi)

Divide by 2(pi) on both sides

r=8 units

Area=(pi)r^2

Area of circle 1=>(pi)*(8^2)

Area of Circle 1=>64(pi) units^2

Circle 2: 2(pi)r=6(pi)

Divide by 2(pi) on both sides

r=3 units

Area=(pi)r^2

Area of circle 2=>(pi)*(3^2)

Area of Circle 2=>9(pi) units^2

3 0

3 years ago

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$