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Solnce55 [7]
3 years ago
10

What is 21/56 simplified

Mathematics
2 answers:
MArishka [77]3 years ago
8 0

Answer:can i have brainliest but its 3/8

Step-by-step explanation:

lozanna [386]3 years ago
3 0
21=3\cdot7\\56=8\cdot7\\\\\frac{21}{56}=\frac{3\cdot\not7^1}{8\cdot\not7_1}=\boxed{\frac{3}{8}}
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Well when you do a problem and it's multiplication and you have to us your math skills and then when you get it wrong don't that
masha68 [24]
Not necessarily. You could have done your multiplication wrong. Or in some cases, yes, you could have to use another skill. For example, you can't solve an optimization problem with addition, you need some calculus skills under your belt.
8 0
3 years ago
An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y
aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                               P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average time = 23.92 minutes

             s = sample standard deviation = 6.72 minutes

             n = sample of times = 40

             \mu = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u>\mu<u> is; </u>

P(-2.426 < t_3_9 < 2.426) = 0.98  {As the critical value of z at 1%  level

                                               of significance are -2.426 & 2.426}  

P(-2.426 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.426) = 0.98

P( -2.426 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.426 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u>98% confidence interval for</u> \mu = [ \bar X-2.426 \times {\frac{s}{\sqrt{n} } } , \bar X+2.426 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 23.92-2.426 \times {\frac{6.72}{\sqrt{40} } } , 23.92+2.426 \times {\frac{6.72}{\sqrt{40} } } ]  

                                    = [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0
3 years ago
PLEASE I NEED URGENT HELP
kari74 [83]

Answer:

D

Step-by-step explanation:

the exterior angle ACD = m< 1+ m <2 = 56+54 = 110

6 0
3 years ago
Read 2 more answers
Due soon! Answer this geometry question. Thanks.
jarptica [38.1K]

Answer:

i think  A if  not  sorry

Step-by-step explanation:

7 0
3 years ago
What is 40% of 10?<br> I need to know this for a math question on khan academy
hodyreva [135]

Answer:

4

Step-by-step explanation:

10/100=0.1

1% = 0.1

0.1*40= 4

8 0
3 years ago
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