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bonufazy [111]
3 years ago
10

a theater group made appearances in two cities. the hotel charge before tax in the second city was $1000 lower than the first. T

ax in the first city was 8% and tax in the second city was 7%. The total hotel tax paid for the two cities was $455. How much was the hotel charge in each city before tax?
Mathematics
1 answer:
expeople1 [14]3 years ago
4 0
I think it is 500 or 300 I really just guessed sorry
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Student A starts with $100 in the bank and makes $5 a day. Student B starts with $50 and makes $7 a day. Assuming the students save their money, when will they have the same amount of money ?
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sorry again for asking this but can someone explain this and give me the answer. Been having a hard time learning this.
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3 years ago
Find the indefinite integral using the substitution provided.
Nady [450]

Answer:  7\text{Ln}\left(e^{2x}+10\right)+C

This is the same as writing 7*Ln( e^(2x) + 10) + C

=======================================================

Explanation:

Start with the equation u = e^{2x}+10

Apply the derivative and multiply both sides by 7 like so

u = e^{2x}+10\\\\\frac{du}{dx} = 2e^{2x}\\\\7\frac{du}{dx} = 7*2e^{2x}\\\\7\frac{du}{dx} = 14e^{2x}\\\\7du = 14e^{2x}dx\\\\

The "multiply both sides by 7" operation was done to turn the 2e^(2x) into 14e^(2x)

This way we can do the following substitutions:

\displaystyle \int \frac{14e^{2x}}{e^{2x}+10}dx\\\\\\\displaystyle \int \frac{1}{e^{2x}+10}14e^{2x}dx\\\\\\\displaystyle \int \frac{1}{u}7du\\\\\\\displaystyle 7\int \frac{1}{u}du\\\\\\

Integrating leads to

\displaystyle 7\int \frac{1}{u}du\\\\\\7\text{Ln}\left(u\right)+C\\\\\\7\text{Ln}\left(e^{2x}+10\right)+C\\\\\\

Be sure to replace 'u' with e^(2x)+10 since it's likely your teacher wants a function in terms of x. Also, do not forget to have the plus C at the end. This is a common mistake many students forget to do.

To verify the answer, you can apply the derivative to it and you should get back to the original integrand of \frac{14e^{2x}}{e^{2x}+10}

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2 years ago
he graph represents function 1, and the equation represents function 2: A coordinate plane graph is shown. A horizontal line is
Reika [66]

Answer:

The answer is 2

Step-by-step explanation:

Rate of change of function is given by :

\frac{(f(x_{2})-f(x_{1}))}{x_{2}-x_{1}}

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For function y = 2·x + 7,

rate of change =

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So, the rate of change of 2 is greater than rate of change of function 1 by 2 - 0 = 2.




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