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3 years ago

Solve for T: PV=nRT

Mathematics

2 answers:

Natali [406]3 years ago

5 0

$T= \frac{PV}{nR}$

Then just plug in your numbers

Yakvenalex [24]3 years ago

4 0

Divide both sides by nR
(PV)/(nR)=T

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

3 years ago

Please help! Correct answer only please!

victus00 [196]

The answer would be A , that’s his slugging percentage ! Hope this helps !

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3 years ago

Junior's brother is 1 1/2

AlladinOne [14]

Answer:

Step-by-step explanation:

1 1/5 of 1 1/2 meters

= (1+1/5) x (1+1/2)

= 1x1 + 1x1/2 + 1x1/5 + 1/5*1/2

= 1 + 1/2 + 1/5 + 1/10

= 1 + (1x5+1x2+1)/10

= 1 8/10

= 1 4/5 meters

6 0

3 years ago

What is the area of the triangle?

alexandr402 [8]

Answer:

15/2

Step-by-step explanation:

Hello,

the area of a triangle is b*h/2

we can set BC as the base because AC is harder to calculate.

Then we draw an imaginary height.

There's no way to really explain, but the height would be 5 here, since 3 - -2 = 5

The base is 3

3*5/2 = 15/2

Thanks,

lacampanella

3 0

3 years ago

a pumpkin falls of a fence that is 3.0 m high (Accelerations due to gravity is 10 m/s *squared ) How fast does the pumpkin hit t

Rufina [12.5K]

3 seconds.

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3 years ago