All categories

3 years ago

Solve for T: PV=nRT

Mathematics

2 answers:

Natali [406]3 years ago

5 0

$T= \frac{PV}{nR}$

Then just plug in your numbers

Yakvenalex [24]3 years ago

4 0

Divide both sides by nR
(PV)/(nR)=T

You might be interested in

Identify a transformation of the function f(x) = x^2 by observing the equation of the function g(x) = (x - 6)^2

MArishka [77]

Answer:

Step-by-step explanation:

Anything inside the bracket affects x opposite of the sign.

Look at it as if you’re solving for x:

x-6=0
x=6

therefore x moves 6 units to the right.

3 0

3 years ago

The speeds in miles per hour of seven randomly selected qualifiers for the Indianapolis 500 (in 2012) are listed below. Estimate

SSSSS [86.1K]

Answer:

Mean qualifying speed

= 224.5669mi/hr

Speed that passed the average/mean

= 226.240mi/hr ,224.037mi/hr 226.484mi/hr, 225.172 mi/hr

Step-by-step explanation:

Let's understand what mean is then understand what mean qualifying speed is.

First mean is like the average of the seven speed listed below.

So let's find the mean.

Mean = (223.684+ 222.929+ 226.240

+224.037 +226.484+ 225.172

+223.422)/7

Mean = 1571.968/7

Mean = 224.5669

So the mean qualifying speed is those speed that qualifies when the mean is taken, i.e the speed that crossed the average.

Mean qualifying speed are

=226.240 ,224.037,226.484

, 225.172

4 0

3 years ago

What is the expected value of X?

Nikitich [7]

Answer:678

Step-by-step explanation:im dumb

4 0

2 years ago

Thom needs 3/4 yard of brown fabric, 2/4 yard of blue fabric, and 3/4 yard of green fabric to make some costumes for a play.

kherson [118]

Answer:

Step-by-step explanation:

Hey there!

I think that some of the content in your question is missing so I will be solving for how much yards of fabric is needed in total

Since all of the fractions have common denominators, we can comfortably add them together

3/4+3/4+2/4 is 8/4

8/4 can be simplied to 2

So the total amount of yards of fabric Thom needs in total is 2 yards

5 0

2 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago