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kkurt [141]
3 years ago
5

ONE QUESTION ONLY!!!

Mathematics
2 answers:
Andrews [41]3 years ago
6 0
Let first number = X and 2nd number = Y

Equation 1: 5X + 8Y = -13

Equation 2: 5X + 10Y = -15

Multiply equation 1 by -1 to get: -5X + -8Y = 13

Now add the 2 equations together:
-5X + 5X = 0

-8Y + 10Y = 2Y

13 + -15 = -2

The total of the 2 equations is 2Y = -2

divide both sides by 2 to solve for Y
Y = -2 / 2
Y = -1
 Now we know the 2nd number is -1, so replace Y in the 1st equation and solve for X

5X +8(-1) = -13

5x + -8 = -13

Add 8 to both sides:
5x = -5

Divide both sides by 5 to get x

X = -5 / 5
X = -1

Both numbers are -1

To check replace X and Y with -1 and solve:

1st equation: 5(-1) +8(-1) = -5 + -8 = -13  TRUE

2nd equation: 5(-1) +10(-1) = -5 + -10 = -15 TRUE

Both numbers are -1





Sedaia [141]3 years ago
3 0

1st number be x, 2nd number be y

Adding 5 times the first number and 8 times the second number gives a total of -13

so 5x+8y=-13

Adding 5 times the first number and 10 times the second number gives -15

so 5x+10y=-15

subtracting the above two eqns

(5x+8y)-(5x+10y) = -13-(-15)

-2y=2

y=-1

put back in first eqn 5x+8(-1)=-13

5x=-5

x=-1


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Pie
The right answer is -13/12.
4 0
3 years ago
In a study relating the degree of warping, in mm, of a copper plate (y) to temperature in °C (x), the following summary statisti
elena-14-01-66 [18.8K]

Answer:

a)

y = 0.3035 + 0.0082x

b)

0.6315 mm

c)

x = 23.9634 °C

Step-by-step explanation:

a. Compute the least-squares line for predicting warping from temperature. Round the answers to four decimal places.

We need to find an equation of the form

y = b + mx

where m is the slope and b the Y-intercept.

The slope m can be computed with the formula

\bf m=\displaystyle\frac{\displaystyle\sum_{i=1}^n(x_i-\bar x)(y_i-\bar y)}{\displaystyle\sum_{i=1}^n(x_i-\bar x)^2}

Replacing the values in our formula (we will round at the end of the calculations)

\bf m=\displaystyle\frac{806.94}{98,775}=0.008169476

the Y-intercept b is computed with the formula

\bf b=\bar y-m\bar x

therefore we have

\bf b=0.5188-0.008169476*26.36=0.303452613

and the least-squares line rounded to 4 decimals would be

y = 0.3035 + 0.0082x

b. Predict the warping at a temperature of 40°C. Round the answer to three decimal places.

We simply replace x with 40 to get

y = 0.3035 + 0.0082*40 = 0.6315 mm

c. At what temperature will we predict the warping to be 0.5 mm? Round the answer to two decimal places

Here, we replace y with 0.5 and solve for x

0.5 = 0.3035 + 0.0082x ===> x = (0.5-0.3035)/0.0082 ===>

 

x = 23.9634 °C

6 0
4 years ago
Twice the sum of consecutive numbers n and n + 1 is 510. What is the smaller number?
guajiro [1.7K]

Answer:

The smaller number is 127

Step-by-step explanation:

Lets write the given problem in equation form

sum of consecutive numbers n and n + 1 = n + n + 1 = 2n + 1

now we find twice of the sum of consecutive numbers n and n + 1

2*(2n + 1) = 4n + 2

given that

twice the sum of consecutive numbers n and n + 1 is 510

thus,

4n + 2 = 510

=> 4n = 510 -2 = 508

=> n = 508/4 = 127

Thus, the numbers are n = 127

n+1 = 127 + 1 = 128

the smaller number is 127

4 0
3 years ago
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BigorU [14]
What do you need help with???
7 0
3 years ago
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Write 16^8 as a power with a base of 4
ruslelena [56]

(4^2)^8 would be the answer 4^2=16 and 16^8 is the same thing

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3 years ago
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