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3 years ago

Please help i dont understand

Mathematics

1 answer:

umka21 [38]3 years ago

6 0

Answer:

Part a)

We need to find the equation of the line with a slope of -5 and a y-intercept of (0,3)

Part b)

The information that we have; we know the value of he slope, -5, and the y-intercept (0,3).

Part c)

strategies to use;

we can use the standard form of the equation of a straight line in slope -intercept form;

y=mx+c

Step-by-step explanation:

We have been given the slope is -5, thus the value of m is -5. moreover, the y-intercept is given as, (0,3) thus c is 3.

Final answer to the problem is;

y=-5x+3

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Maurinko [17]

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4 years ago

2 sin^2 (x) -5 sin (x) -3=0

andreyandreev [35.5K]

we have that

$2sin^{2} x-5sin x-3=0$

I. Rewrite the equation by substituting the expression u in for sin x.

$2u^{2} -5u-3=0$

II. Factor the quadratic expression. Rewrite the equation with factors instead of the original polynomial.

$2u^{2} -5u-3=0$ is equal to

using a graph calculator-----> see the attached figure

$(u-3)*(2u+1)=0$

III. Use the zero product property to solve the quadratic equation.

$(u-3)*(2u+1)=0$

(u-3)=0--------------> u=3

(2u+1)=0-------- 2u=-1------> u=-1/2-----> u=-0.5

IV. Rewrite your solutions to Part III by replacing u with sin x.

sin x=3--------> is not the solution (sin x can not be greater than 1)

sin x=-0.50------>is the solution

V. Solve the remaining equations for x, giving all solutions to the equation.

sin x=-0.50

if the sine is negative

then

x belong to the III or IV quadrant

we know that

sin 30°=0.50

the solution for the III quadrant is

x=180°+30°-------> x=210°

the solution for the IV quadrant is

x=360°-30°------> x=330°

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3 years ago