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3 years ago

11

What is the volume of a square pyramid that has a base length of 5 inches and a height of 9 inches?

1 answer:

PtichkaEL [24]3 years ago

4 0

Well since the for formula for these are b × h. We are gonna do...

5 × 9 which equals 45. So your answer is 45 cubic inches

hope this helps!

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HELPPPPPPPPPPPPPP PLZZZZZZZZZZZ clock arithmetic Will mark brainiest .

GarryVolchara [31]

Answer:

a) 29

b) 0

c) 7

d) 3/8

Step-by-step explanation:

Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.

If the result is negative, you add the clock hours.

a) 21 - 33 = -12 , so -12 + 41 = 29

b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.

c) 11+19 = 30, 30 - 23 = 7

d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.

7 0

3 years ago

Find y when x = 12, if y = 2 when x = 5

AleksAgata [21]

Y = kx
k = y/x
k = 2/12
k = 1/6

so when x = 12
y = kx
y = 1/6(5)
y = 5/6

answer
when x = 5 y = 5/6

7 0

3 years ago

5 movie tickets cost $55. At this rate, what is the cost per ticket?

Mariana [72]

Answer:

11

Step-by-step explanation:

55/5 equals 11

4 0

2 years ago

Read 2 more answers

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

2 years ago

Bert measured a swimming pool and made a scale drawing. The scale of the drawing was

Cerrena [4.2K]

1/100
Each meter is 100 centimeter

8 0

3 years ago