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Goshia [24]
4 years ago
9

Identify the predictor variable and the response variable. A farmer has data on the amount of precipitation crops received and t

he harvest of the crops. The farmer wants to determine the harvest of his crop based on the amount of precipitation his crop received.
Mathematics
1 answer:
kow [346]4 years ago
7 0

Answer:

The Predictor variable is the amount of precipitation received while the Response variable is the crop harvest.

Step-by-step explanation:

The Response variable in an experiment is the factor being measured or studied. They are also known as the dependent variables. Predictor variables are those values that explain the changes in the Response variable. They are also known as the independent variables.

In the question above, the amount of precipitation provides an explanation for the harvest of his crops. Therefore, the amount of precipitation can be rightly described as the predictor or independent variable, while the harvest of his crops is described as the response or dependent variable.

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Solve the inequality: −34 < −2(4x − 1)
Ne4ueva [31]

- 34 <  - 2(4x - 1) \\  - 34 <  - 8x + 2 \\  - 34 - 2 <  - 8x \\  - 36 <  - 8x \\ 36  > 8x \\  \frac{36}{8}  > x \\ x <   \frac{9}{2}

7 0
3 years ago
Let f be defined by the function f(x) = 1/(x^2+9)
riadik2000 [5.3K]

(a)

\displaystyle\int_3^\infty \frac{\mathrm dx}{x^2+9}=\lim_{b\to\infty}\int_{x=3}^{x=b}\frac{\mathrm dx}{x^2+9}

Substitute <em>x</em> = 3 tan(<em>t</em> ) and d<em>x</em> = 3 sec²(<em>t </em>) d<em>t</em> :

\displaystyle\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\frac{3\sec^2(t)}{(3\tan(t))^2+9}\,\mathrm dt=\frac13\lim_{b\to\infty}\int_{t=\arctan(1)}^{t=\arctan\left(\frac b3\right)}\mathrm dt

=\displaystyle \frac13 \lim_{b\to\infty}\left(\arctan\left(\frac b3\right)-\arctan(1)\right)=\boxed{\dfrac\pi{12}}

(b) The series

\displaystyle \sum_{n=3}^\infty \frac1{n^2+9}

converges by comparison to the convergent <em>p</em>-series,

\displaystyle\sum_{n=3}^\infty\frac1{n^2}

(c) The series

\displaystyle \sum_{n=1}^\infty \frac{(-1)^n (n^2+9)}{e^n}

converges absolutely, since

\displaystyle \sum_{n=1}^\infty \left|\frac{(-1)^n (n^2+9)}{e^n}\right|=\sum_{n=1}^\infty \frac{n^2+9}{e^n} < \sum_{n=1}^\infty \frac{n^2}{e^n} < \sum_{n=1}^\infty \frac1{e^n}=\frac1{e-1}

That is, ∑ (-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ converges absolutely because ∑ |(-1)ⁿ (<em>n</em> ² + 9)/<em>e</em>ⁿ| = ∑ (<em>n</em> ² + 9)/<em>e</em>ⁿ in turn converges by comparison to a geometric series.

5 0
3 years ago
[super easy] i have to draw an ugly sweater based around the vocab term natural selection, any ideas?
Keith_Richards [23]
Maybe make it a Christmas tree picking
7 0
3 years ago
39/51 change to lowest terms
OLEGan [10]

Answer:

As a proper fraction  - 39/51 = 13/17

As a decimal number:  39/51 ≈ 0.76

As a percentage:  39/51 ≈ 76.47%

Step-by-step explanation:

Calculate the greatest (highest) common factor (divisor), gcf (gcd).

13/17 =

13 ÷ 17 =

0.764705882353 ≈

0.76

By precentage

0.764705882353 =

0.764705882353 × 100/100 =

76.470588235294/100 =

76.470588235294% ≈

76.47%

7 0
3 years ago
Venell put together a model train with 25 train cars. Each train car is 80 millimeters long. How many meters long is Venell's mo
Aliun [14]

Answer:

So the answer is 2 meters

Step-by-step explanation:

So it's easy all you have to do is multiply 25

                                                                 x 80

                                                                 _____

                                                                  2,000/1,000=2

The reason I divided by 1,000 is because it says you need to convert it to meters instead of just millimeters.

                                                                 

8 0
3 years ago
Read 2 more answers
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