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Andreas93 [3]
3 years ago
12

The midpoint of mn is point p at (-4,6). If point m is at (8,-2), what are the coordinates of point n?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
7 0
<u>x₁ + x₂</u>                             <u>y</u>₁ + <u>y</u>₂<u>
</u>     2      = M                        2     = M
<u>
x + 8</u>                                 <u>y + -2</u><u>
</u>    2    = -4                            2           =6
<u>multiply both sides by 2.

</u>x+8=-8                             y - 2 = 12
<u>x = -16</u>                             <u>y = 14
</u>
Final Answer: (-16, 14)



evablogger [386]3 years ago
6 0
The midpoint of 2 points is basicaly the average of th points

so
(x1,y1) and (x2,y2)
the midpoint x value is (x1+x2)/2
midpoint y value is (y1+y2)/2

so

midpoint is (-4,6)
a point i (8,-2)
so then
the missing point is (x2,y2)
so
(x2+8)/2=-4
x2+8=-8
x2=-16

(y2-2)/2=6
y2-2=12
y2=14

the point n is (-16,14)
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Read 2 more answers
Solve for x:<br> 4x – 7 = 8x + 33
Lera25 [3.4K]

Answer:

x = 10

Step-by-step explanation:

Hey there!

To solve this question we will use PEMDAS (order of operations)

4x−7=8x+33

Subtract 8x from both sides.

4x−7−8x=33

Combine 4x and −8x to get −4x.

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Add 7 to both sides.

−4x=33+7

Add 33 and 7 to get 40.

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Divide both sides by −4.

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Divide 40 by −4 to get −10.

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