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diamong [38]
3 years ago
15

A cable runs from the top of a pole to a spot on the ground 10 feet from the base of the pole. The pole makes a right angle with

the ground. If the cable is 20 feet long, what is the angle the cable makes with the ground? Enter your answer in degrees.
Mathematics
1 answer:
Amanda [17]3 years ago
7 0
Use the cos ratio to figure this out. You have the length of the hypotenuse and the length of the leg on the ground. The hypotenuse is 20 and the leg is 10. The cos ratio says that cosA = side adjacent/hypotenuse. So fill in the blanks here: cosA = 10/20...cosA=1/2. In your calculator, you will enter inverse cos(.5) to find that the angle in question is 60 degrees. To find the inverse function on your calculator, press the "2nd" button and the "cos" then in the (), enter ".5".
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Please answer 46 points. Do not comment if u don’t know
Alex787 [66]

Answer: 1ST ONE CUZ THE LINE IS AT A CERTAIN ANGLE AT A POINT TO MATCH THE FIRST ANSWER

Step-by-step explanation:

7 0
2 years ago
Meghan made $458 in her last paycheck. If she would like to save at least $175 of it, how much can she spend?
Olenka [21]

Answer: $283

Step-by-step explanation:

If you subtract 458-175 you get 283 so that how much Megan can spend.

3 0
2 years ago
Find the area of the following ellipse (round to nearest tenth).
goblinko [34]

Answer:

\huge\boxed{A=60\pi cm^2}

Step-by-step explanation:

The formula of an area of a elipse:

A=\pi ab

We have:

2a=10cm\to a=5cm\\\\2b=24cm\to b=12cm

Substitute:

A=\pi\dot5\cdot12=60\pi(cm^2)

8 0
2 years ago
Please actually answer this it has a good amount of points!
Vanyuwa [196]

The answer is D, "No, because two points with the same x-value have different y-values."

Essentially, there cannot be more than one point on the same x-line. Point (2, 11) and point (2, 2) are on the same x-line, which is 2.

Hope this helps!

6 0
3 years ago
Find the error (-8x^2y^2)^2= -64x^4y^4
ExtremeBDS [4]

Answer:

(-8)^2\neq-64

Step-by-step explanation:

Using the distributive property to expand, we have

(-8x^2y^2)^2=(-8)^2(x^2)^2(y^2)^2.

Squaring each term, we have

(-8x^2y^2)^2=64x^4y^4.

The mistake was that 8^2=64, not -64. Using the fact that 8^2=64, the right answer would be

\boxed{64x^4y^4}.

3 0
2 years ago
Read 2 more answers
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