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3 years ago

This question is hard and I don’t know it may u please help

Mathematics

1 answer:

zloy xaker [14]3 years ago

4 0

Answer:

Mark's total salary is 22,260

Step-by-step explanation:

well, his base salary is 21,000.

if you look at the diagram, the added bonus is 6% of the base salary.

6% can be rewritten as 0.06

0.06 * 21,000 = 1,260

the total salary is just the base salary and the bonus salary added together.

21,000 + 1,260 = 22,260

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Bas_tet [7]

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3 years ago

What’s the x-intercepts

vovikov84 [41]

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3 years ago

Facts about pasical's education

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3 years ago

The package shown is shaped like a right rectangular prism. Every side of the package will be covered with gift wrap, except the

Alexxandr [17]

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3 years ago

A group of researchers are interested in the possible effects of distracting stimuli during eating, such as an increase or decre

Dmitry [639]

Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

At the null hypothesis, it is tested if the consumption is not different, that is, if the subtraction of the means is 0, hence:

$H_0: \mu_1 - \mu_2 = 0$

At the alternative hypothesis, it is tested if the consumption is different, that is, if the subtraction of the means is not 0, hence:

$H_1: \mu_1 - \mu_2 \neq 0$

Two groups of 22 patients, hence, the standard errors are:

$s_1 = \frac{45.1}{\sqrt{22}} = 9.6154$

$s_2 = \frac{26.4}{\sqrt{22}} = 5.6285$

The distribution of the differences is has:

$\overline{x} = \mu_1 - \mu_2 = 52.1 - 27.1 = 25$

$s = \sqrt{s_1^2 + s_2^2} = \sqrt{9.6154^2 + 5.6285^2} = 11.14$

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{s}$

In which $\mu = 0$ is the value tested at the null hypothesis.

Hence:

$t = \frac{25 - 0}{11.14}$

$t = 2.2438$

The p-value of the test is found using a two-tailed test, as we are testing if the mean is different of a value, with t = 2.2438 and 22 + 22 - 2 = 42 df.

Using a t-distribution calculator, this p-value is of 0.0302.

Since the p-value of the test is of 0.0302, which is less than the standard significance level of 0.05, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.

A similar problem is given at brainly.com/question/25600813

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3 years ago