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erica [24]
1 year ago
5

The green basilisk enclosure will include a rectangular pond in one corner. The width of the

Mathematics
1 answer:
Hunter-Best [27]1 year ago
7 0

After factorization we get the two terms ( w - 3 ) ( w + 2 )

And the values of  A and B as 3 and 2 respectively .

That is A = 3 and B = 2.

The given expression is w² - w - 6.

This question can be calculated easily by middle term split

First step is to multiply the first and the last term

which will give us - 6

thus now we have to look for two number which when either added or subtracted will give us - 1

Thus we can write it as :

w² - 3 w + 2 w - 6

Now take the terms which are common

and we will get

w ( w - 3 ) + 2 ( w - 3 )

( w - 3 ) ( w + 2 )

Thus if we compare it with (w - A) (w + B)

we will get the values of A and B as

3 and 2 respectively .

That is A = 3 and B = 2

To know more about factorization you may visit the link which is mentioned below:

brainly.com/question/20293447

#SPJ13

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Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has
RUDIKE [14]

Answer:

1)    

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW        0.01             0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05  

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) =  0.025 - 0.015 = 0.01

THEREFORE  the Bivariate Table;

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW       0.01              0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3)  probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% =  0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0
3 years ago
If x = 2 and y=-3, then -xy^2 =<br> A) -36<br> B) 18<br> C) -12<br> D) - 18
Citrus2011 [14]

Answer:

-18

Step-by-step explanation:

-xy^2 =

Let x=2 and y = -3

-(2) (-3)^2

-2 (9)

-18

4 0
3 years ago
Sandy has box of chocolates. Box cost $2.00. In box has 8 chocolates. How much does each chocolate cost.
Lorico [155]
So you must find individual prices.


Start by doing the price($2.00)divided by the amount in box(8) 


you should get 0.25 or 25 cents per chocolate
5 0
3 years ago
Read 2 more answers
When three squares are joined at their vertices to form a right triangle, the combined area of
zlopas [31]

Answer:

..

Step-by-step explanation:

3 0
3 years ago
A cylinder has a volume of 45pi and a radius of 3. What is it’s height?
Svetllana [295]

Answer:

<h2>        It’s height is <u> 5 </u> units.</h2>

Step-by-step explanation:

V=\pi R^2\cdot H\\\\V=45\pi\\R=3\\H=??\\\\45\pi=\pi\cdot3^2\cdot H\\\\45=9H\\\\H=5

8 0
2 years ago
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