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vagabundo [1.1K]
1 year ago
5

Solve this equation for X. If necessary, round your answer to the nearest integer

0%202%29%5E%7B%20%5Cfrac%7B1%20%7D%7B3%7D%20%3D%20%20-%202" id="TexFormula1" title="(2x + 2)^{ \frac{1 }{3} = - 2" alt="(2x + 2)^{ \frac{1 }{3} = - 2" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
devlian [24]1 year ago
6 0
The answer is x = 1 :)
Hatshy [7]1 year ago
5 0

Answer

x = 1

Explanation:

Given the following equation

\begin{gathered} (2x+2)^{\frac{1}{2}}=\text{ -2} \\ \text{According to the law of indicies} \\ x^{\frac{1}{2}}\text{ = }\sqrt[]{x} \\ (2x+2)^{\frac{1}{2}}\text{ = }\sqrt[]{(2x\text{ + 2)}} \\ \text{Step 1: Take the square of both sides} \\ \sqrt[]{(2x\text{ + 2) }}\text{ = -2} \\ \sqrt[]{(2x+2)^2}=-2^2 \\ 2x\text{ + 2 = 4} \\ \text{Collect the like terms} \\ 2x\text{ = 4 - 2} \\ 2x\text{ = 2} \\ \text{Divide both sides by 2} \\ \frac{2x}{2}\text{ = }\frac{2}{2} \\ x\text{ = 1} \end{gathered}

Therefore, x = 1

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Answer:

The answer to this question can be described as follows:

Step-by-step explanation:

Given equation:

\bold{0.5x-7= \sqrt{(-5x+29)}}

As in the given question the two ways to solve the equation can be defined as follows:

First way:

Let square the above-given equation then we will get:

\to (0.5x-7)^2= (\sqrt{(-5x+29)})^2\\\\\to (0.5x)^2 +7^2-2\times 0.5x\times 7= -5x+29\\\\\to 0.25x^2 +49- 7x= -5x+29\\\\\to 0.25x^2 - 7x+5x +49-29=0\\\\\to 0.25x^2 - 2x+20=0\\\\

The calculated equation doesn't have any like term that's why it can't be factorised.

Second way:

after calculating the equation that is 0.25x^2-2x+20=0, it graph is given in attachment please find.

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3 years ago
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