Answer:
m=7 z=-12
Step-by-step explanation:
expand brackets:
8m+24=5m+45
Change sides:
8m-5m=45-24
3m=21
<u>m=7</u>
<u />
<u>z-6</u> = <u>3</u>
2z 4
Coss multiply:
4z-24=6z
4z-6z=24
-2z=24
Divide both sides by -2:
z=-12
Answer:
Variant c
Step-by-step explanation:
c²=4*9
c=6
You can apply phyphagor
b²=6²+9²=36+81=117
The answer will be -22x^2-14x. Hope it help!
Answer:
One possible answer would be they sold 80 student tickets and 30 adult tickets
Step-by-step explanation:
set up two inequalities, one to show number of tickets that can be sold, and the other is how much money they need to make
5x+10y G than or = 700
x+y L than or = 110
The first inequality shows that each student (x) ticket sells for $5, and each adult (y) ticket sells for $10, and the amound has to be greater or equal to 700.
The second inequality shows that both student and adult tickets sold have to be less than or equal to 110.
First find either x or y, in this case finding y was easier
y is g than or = to 30
This means that they sold at least 30 adult tickets= $300
With y, plug into the inequality x+y L than or = to 110 to find x
x is less than or = to 80
This means that they sold at most 80 student tickets = $400
Hope this helps!
Answer:
I predict it would be $45
Step-by-step explanation:
