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Paul [167]
2 years ago
13

The table shows the number of free throws a player makes in a basketball game and the number of points the player scores in the

game. Number of Free Throws vs. Number of Points Scored Number of Free Throws Made (f) Number of Points Scored (s) 5 17 8 22 9 23 12 31 13 35 Bianca graphs the data in the table and finds that the trend line is s = 2.2 f + 4.7. Based on the information given, a player who makes 22 free throws in a game should score about how many points? 39 44 53 66
Mathematics
2 answers:
Viefleur [7K]2 years ago
8 0

the answer is C, 53

thank you have a great day ;)

Nitella [24]2 years ago
7 0

Answer:

C: 53

Step-by-step explanation:

edg2021

(100 on quiz)

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ThE RADIUS of CIRCLE
Firlakuza [10]

Answer:

31.4

Step-by-step explanation:

Because you multiply the circumference by pi

6 0
2 years ago
Need Help On This Problem PLZ :-)
anastassius [24]

Answer:

y = 9 + 19x

Step-by-step explanation:

To find the equation matching a set of data, you simply try a few values for x and see if by solving that side of the equation you get the value of y.  If you do, you found your equation.

You have a big advantage here... since you have the value of y when x = 0.

When x = 0, y = 9, that's a very important data to have to simplify your research.

Let's try the value of 0 for x in each of the given equations:

y = 18 + 10 (0) = 18  --- NO

y = 9 + 19 (0) = 9 --- YES!  We can confirm with another value of x:

y = 9 + 19 (1) = 28 --- YES! Confirmed!

y = 9 + 19x is your answer!

8 0
3 years ago
Write a quadratic equation, in factored form solution are 0,and 6
Salsk061 [2.6K]

Answer: x(x-6)=0

4 0
2 years ago
Can I get help solving this graph please?
Daniel [21]
see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100)  B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40)  C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0)  B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60)  C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then 
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x) 
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then 
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x) 
h'(x)=18/25=0.72 

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0
3 years ago
Jim went to the playground. He played on the swings for 45 minutes and went on the slide for 55 minutes. It was 4:35 P.M. when J
aleksklad [387]

Answer:

2:55 P.M.

Step-by-step explanation:

First, add the amount of time Jim played outside; 45+55=100

100 minutes is equal to 1 hour 40 minutes.

If he left the playground at 4:35 P.M., then you have to subtract in order to find out when he arrived there.

Subtract 1 hour 40 minutes from 4:35 P.M. to then get 2:55 P.M.

To confirm your answer, you can add back the 1 hour and 40 minutes to 2:55 P.M. and you'll get 4:35 P.M.; back with what you started with.

Hope this helped !!!

4 0
3 years ago
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