Question

A local am radio station broadcasts at a frequency of 764 khz. calculate the energy of the frequency at which it is broadcasting. energy = kj/photon

Answer 1

The frequency of the emitted radio waves is:
$f=764 kHz = 7.64 \cdot 10^5 Hz$

The energy of a photon is given by:
$E=hf$
where h is the Planck constant and f is the photon frequency. Using the frequency given by the problem, we can find the energy of each photon of this radiation:
$E=hf=(6.6 \cdot 10^{-34} Js)(7.64 \cdot 10^5 Hz)=5.04 \cdot 10^{-28} J=5.04 \cdot 10^{-31} kJ$