What is the slope of a line that passes through the points (-2, 0) and (-4, -3)?
1 answer:
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Step-by-step explanation:
the line given slope = x coefficient = -5/2
Perpendicular slopes must be opposite reciprocals of each other: m1 * m2 = –1
new slope = 2/5
line equation formula = y = mx+ b
m = slope
y= 2/5x + b
from the point given (-6,0)
x = -6
y = 0
0= -12/5 + b
b = +12/5
line equation =