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Wewaii [24]
3 years ago
6

A 500 cm piece of wire with a radius of 0.2 cm has a resistance of 0.025 ohm. Find an equation that relates these variables.

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

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Write as a single logarithm
Anettt [7]

ANSWER

c. \ln( \frac{2 {x}^{3} }{3y})

EXPLANATION

We want to write

ln(2x)  + 2 ln(x)  -  ln(3y)

as a single logarithm.

Use the power rule to rewrite the middle term:

n \:  ln(a)  =  ln( {a}^{n} )

ln(2x)  +  ln( {x}^{2} )  -  ln(3y)

Use the product rule to obtain:

ln(a)  +  ln(b)   =  ln(ab)

ln(2x \times  {x}^{2} )-  ln(3y)

ln(2{x}^{3} )-  ln(3y)

Apply the quotient rule:

ln(a)  -   ln(b) = ln( \frac{a}{b})

ln(2{x}^{3} )-  ln(3y) =\ln(\frac{2 {x}^{3} }{3y})

7 0
3 years ago
The graph below shows the solution set of which inequality?
GrogVix [38]

Answer:

The answer is the option D

x^{2} > 4

Step-by-step explanation:

we know that

The inequality

x^{2} > 4

has two solutions

<u>First solution</u>

x > 2

The solution is the interval-------> (2,∞)

All real numbers greater than 2

<u>Second solution</u>

-x > 2------>x < -2-

The solution is the interval-------> (-∞,-2)

All real numbers less than -2

using a graphing tool

see the attached figure


3 0
3 years ago
Read 2 more answers
Whats the distance between (-3,4) and (5,1)?
guajiro [1.7K]

Answer:

Step-by-step explanation:

(-3,4) and (5,1)

(-3,4) is in quadrant 2 and (5,1) is in quadrant 1. So think of that.

(x+8, y-3)

8 units to the right and 3 units down

3 0
3 years ago
Read 2 more answers
State the degree: 11m^3n^2p
Vadim26 [7]
<h3>Answer:  6</h3>

Explanation:

Using the rule that x = x^1, we can rewrite the p as p^1

So 11m^3n^2p is the same as 11m^3n^2p^1

The exponents are: 3, 2, 1

Those exponents add up to 3+2+1 = 6

The degree of a monomial like this is simply equal to the sum of the exponents.

7 0
3 years ago
Read 2 more answers
Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=
Genrish500 [490]

Answer:

f'''(x)=\frac{3}{x^{2}}

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

f''(x)=9-\frac{3}{x}

We need to find Third-order derivative of the function f(x).

f''(x)=9-\frac{3}{x}=9-3x^{-1}

We know that,

f'''(x) = (f''(x))'

So,

f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}

f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}

f'''(x)=-3(-1)x^{-1-1}

f'''(x)=3x^{-2}

f'''(x)=\frac{3}{x^{2}}

Therefore, f'''(x)=\frac{3}{x^{2}}

4 0
4 years ago
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