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Wewaii [24]
3 years ago
6

A 500 cm piece of wire with a radius of 0.2 cm has a resistance of 0.025 ohm. Find an equation that relates these variables.

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

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Find the length of the missing side of the triangle. The lengths of the triangles are 5m and 14m. The answer choices are:
torisob [31]
I guess you mean 5m and 14m are the lengths of 2 sides of the triangle.

If  the length of any side is equal or greater than the sum of the other 2 sides then you can;t make a triangle.

So for example  19 cannot  the answer because 19 = 5 + 14 .  No triangle can be formed with sides that measure.
and 38 is greater than 14 + 5 so its cant be C.


The answer is A
4 0
4 years ago
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Consider the quadratic equation x2 - 6x - 16 = 0. A. Solve the equation, and discuss how the type of roots affects the appearanc
Goryan [66]
I've attached working :)

4 0
4 years ago
5^-x +7=2x+4 solution
vodomira [7]

Simplifying

5x + 7 = 2x + 4

Reorder the terms:

7 + 5x = 2x + 4

Reorder the terms:

7 + 5x = 4 + 2x

Solving

7 + 5x = 4 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x' to each side of the equation.

7 + 5x + -2x = 4 + 2x + -2x

Combine like terms: 5x + -2x = 3x

7 + 3x = 4 + 2x + -2x

Combine like terms: 2x + -2x = 0

7 + 3x = 4 + 0

7 + 3x = 4

Add '-7' to each side of the equation.

7 + -7 + 3x = 4 + -7

Combine like terms: 7 + -7 = 0

0 + 3x = 4 + -7

3x = 4 + -7

Combine like terms: 4 + -7 = -3

3x = -3

Divide each side by '3'.

x = -1

Simplifying

x = -1

4 0
3 years ago
Compute the amount of interest earned in the following simple interest problem. A deposit of $1,600 at 6% for 180 days =
Nikitich [7]
6% of $1,600 is = 96 if you multiple it with 180 : 96 × 180 = 17,280
7 0
4 years ago
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Question 7 of 10
Ganezh [65]

Answer:

  • Option B

Step-by-step explanation:

Given Equation :

\qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2

Using distribute property:

\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2

Adding the like terms we get :

\qquad \sf \dashrightarrow \: 12x + 9 = 2x  + 5x  - 15 + 2

\qquad \sf \dashrightarrow \: 12x + 9 = 7x  - 13

Transposing the variables on the right side and constant terms on the left side :

\qquad \sf \dashrightarrow \: 12x  - 7x =   - 13 - 9

\qquad \sf \dashrightarrow \: 5x =   - 22

Dividing both sides by 5 :

\qquad \sf \dashrightarrow \:  \dfrac{5x}{5}  =  \dfrac{ - 22}{5}

\qquad \bf \dashrightarrow \:  x =  \dfrac{ - 22}{5}

3 0
3 years ago
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