All categories

3 years ago

Pls help 7th grade math

Mathematics

1 answer:

NeX [460]3 years ago

7 0

Ok you would just need to add those together

4 1/2 + 3 3/4 + 8 1/5 + 1 1/3 = 33 36/60

this is what i got when i add them together :) have a great day

You might be interested in

Please dont ignore, Need help!!! Use the law of sines/cosines to find..

Ket [755]

Answer:

16. Angle C is approximately 13.0 degrees.

17. The length of segment BC is approximately 45.0.

18. Angle B is approximately 26.0 degrees.

15. The length of segment DF "e" is approximately 12.9.

Step-by-step explanation:

By the law of sine, the sine of interior angles of a triangle are proportional to the length of the side opposite to that angle.

For triangle ABC:

$\sin{A} = \sin{103\textdegree{}}$ ,
The opposite side of angle A $a = BC = 26$ ,
The angle C is to be found, and
The length of the side opposite to angle C $c = AB = 6$ .

$\displaystyle \frac{\sin{C}}{\sin{A}} = \frac{c}{a}$ .

$\displaystyle \sin{C} = \frac{c}{a}\cdot \sin{A} = \frac{6}{26}\times \sin{103\textdegree}$ .

$\displaystyle C = \sin^{-1}{(\sin{C}}) = \sin^{-1}{\left(\frac{c}{a}\cdot \sin{A}\right)} = \sin^{-1}{\left(\frac{6}{26}\times \sin{103\textdegree}}\right)} = 13.0\textdegree{}$ .

Note that the inverse sine function here $\sin^{-1}()$ is also known as arcsin.

By the law of cosine,

$c^{2} = a^{2} + b^{2} - 2\;a\cdot b\cdot \cos{C}$ ,

where

$a$ , $b$ , and $c$ are the lengths of sides of triangle ABC, and
$\cos{C}$ is the cosine of angle C.

For triangle ABC:

$b = 21$ ,
$c = 30$ ,
The length of $a$ (segment BC) is to be found, and
The cosine of angle A is $\cos{123\textdegree}$ .

Therefore, replace C in the equation with A, and the law of cosine will become:

$a^{2} = b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}$ .

$\displaystyle \begin{aligned}a &= \sqrt{b^{2} + c^{2} - 2\;b\cdot c\cdot \cos{A}}\\&=\sqrt{21^{2} + 30^{2} - 2\times 21\times 30 \times \cos{123\textdegree}}\\&=45.0 \end{aligned}$ .

For triangle ABC:

$a = 14$ ,
$b = 9$ ,
$c = 6$ , and
Angle B is to be found.

Start by finding the cosine of angle B. Apply the law of cosine.

$b^{2} = a^{2} + c^{2} - 2\;a\cdot c\cdot \cos{B}$ .

$\displaystyle \cos{B} = \frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}$ .

$\displaystyle B = \cos^{-1}{\left(\frac{a^{2} + c^{2} - b^{2}}{2\;a\cdot c}\right)} = \cos^{-1}{\left(\frac{14^{2} + 6^{2} - 9^{2}}{2\times 14\times 6}\right)} = 26.0\textdegree$ .

For triangle DEF:

The length of segment DF is to be found,
The length of segment EF is 9,
The sine of angle E is $\sin{64\textdegree}}$ , and
The sine of angle D is $\sin{39\textdegree}$ .

Apply the law of sine:

$\displaystyle \frac{DF}{EF} = \frac{\sin{E}}{\sin{D}}$

$\displaystyle DF = \frac{\sin{E}}{\sin{D}}\cdot EF = \frac{\sin{64\textdegree}}{39\textdegree} \times 9 = 12.9$ .

7 0

3 years ago

Math help please thanks due soon

dezoksy [38]

Problem 11

Answer: Angle C and angle F

Explanation: Angle C and the 80 degree angle are vertical angles. Vertical angles are always congruent. Angle F is equal to angle C because they are alternate interior angles.

============================================

Problem 12

Answer: 100 degrees

Explanation: Solve the equation E+F = 180, where F = 80 found earlier above. You should get E = 100.

============================================

Problem 13

Answer: 80 degrees

Explanation: This was mentioned earlier in problem 11.

============================================

Problem 14

Answers: complement = 50, supplement = 140

Explanation: Complementary angles always add to 90. Supplementary angles always add to 180. An example of supplementary angles are angles E and F forming a straight line angle.

7 0

3 years ago

Yu-Xi draws a triangle with two angles measuring 79 degrees and 23 degrees. What is the measure, in degrees, of the third angle?

Scrat [10]

Answer:

78 Degrees

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Solve on the interval [0,2pi) 3cscx-1=2

aliya0001 [1]

Answer:

on APEX its d) pi/2

3 0

3 years ago

Express each number in its simplest radical form. <br> √6⋅√60=?

Tom [10]

Answer:

6√10

Step-by-step explanation:

factorizing 6 and 60

6 = 2 x 3

60 = 2 x 2 x 3 x 5

hence

√6 · √60

= √ [ (2 x 3) · (2 x 2 x 3 x 5) ]

= √ (2· 2² · 3² · 5)

= √ (2² · 3²) x √(2·5)

= (2 · 3) x √10

= 6√10

5 0

3 years ago

Read 2 more answers