5.01 is greater
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Answer:
54 because I don't know I can't explain
Factor out the GCF. Do not forget to include the GCF as part of your final answer. In this case, the three terms have a 3x in common, which leaves: Step 3: Multiply the leading coefficient and the constant, that is multiply the first and last numbers together.
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that 
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:
Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
Answer:
A. They will pay more with the new price plan.
B. The new price plan would be cheaper.
Step-by-step explanation:
A. They will pay more with the new price plan.
For the current price plan, you would add the $3 rent to the two games (which are $4 each). This basically means:
$3 + $4 + $4 = $11
For the new price plan, you would add the $11 rent to the two games (which are $2 each). This basically means:
$11 + $2 + $2 = $15
Therefore, you pay more for the new price plan.
B. Using similar logic as part A, the current price plan 7 games would cost:
$3 + [7 x ($4)] = $31 (multiply by 7 since they play 7 games)
For the newprice plan, 7 games would cost:
$11 + [7 x ($2)] = $25 (multiply by 7 since they play 7 games)
Therefore, the new price plan would be cheaper.
Hope this helps :)
