Which polynomial function has a root of 3 with multiplicity 2 and roots of –10 and –1 with multiplicity 1? f(x) = (x – 10)(x – 1
)(x + 3)(x + 3) f(x) = x(x – 10)(x – 1)(x + 3) f(x) = (x + 10)(x + 1)(x – 3)(x – 3) f(x) = x(x + 10)(x + 1)(x – 3)(x – 3)
1 answer:
Answer:
(x+10)(x+1)( x-3) ( x-3)
Step-by-step explanation:
root of 3 with multiplicity 2
( x-3) ^2 or ( x-3) ( x-3)
root of -10
(x- -10) is (x+10)
root of -1
(x - -1) is (x+1)
( x-3) ^2 (x+10)(x+1)
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