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3 years ago

What are the coefficents in the expansion of (x+y)^4

Mathematics

1 answer:

Darina [25.2K]3 years ago

8 0

(x+y)4=x^4+4x^3*y+6x^2*y^2+4x*y^3+y^4

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What is the solution of the system? Use the elimination method. {4x+2y=66x−4y=−12

Rina8888 [55]

$\begin{bmatrix}4x+2y=6\\ 6x-4y=-12\end{bmatrix}$

$\mathrm{Multiply\:}4x+2y=6\mathrm{\:by\:}3: 12x+6y=18$
$\mathrm{Multiply\:}6x-4y=-12\mathrm{\:by\:}2: 12x-8y=-24$

$\begin{bmatrix}12x+6y=18\\ 12x-8y=-24\end{bmatrix}$

12x - 8y = -24
-
12x + 6y = 18
/
-14y = -42

$\begin{bmatrix}12x+6y=18\\ -14y=-42\end{bmatrix}$

$Solve\;-14y=-42 \;for\;y \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}-14 \ \textgreater \ \frac{-14y}{-14}=\frac{-42}{-14}$
y = 3

$\mathrm{For\:}12x+6y=18\mathrm{\:plug\:in\:} \:y=3$

$12x+6\cdot \:3=18 \ \textgreater \ \mathrm{Multiply\:the\:numbers:}\:6\cdot \:3=18 \ \textgreater \ 12x+18=18$

$\mathrm{Subtract\:}18\mathrm{\:from\:both\:sides} \ \textgreater \ 12x+18-18=18-18$

$\mathrm{Simplify} \ \textgreater \ 12x = 0 \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}12 \ \textgreater \ \frac{12x}{12}=\frac{0}{12} \ \textgreater \ x = 0$

$Therefore\;the\:solutions\:are\;y=3,\:x=0$

Hope this helps!

5 0

4 years ago

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If p = 7, then what is the value of 8x p- 6?

Alik [6]

Answer:

Step-by-step explanation:

8*7-6

56-6

plzzz mark brainliest

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3 years ago

A school district has 2 teaching positions to fill and there are 8 applicants to choose from. How many different possibilities a

Olenka [21]

I think the answer would be 56. Bc the first job has 8 different people who could get the job and then once someone is chosen for that slot the next teaching position only has 7 candidates. So you would take 8*7 which equals 56.

6 0

3 years ago

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The additive inverse of the complex number a+bi is -a-bi. The sum of a complex number and its additive inverse is zero.

atroni [7]

I think it is 2-8i
Hope this helps

8 0

3 years ago

choose the equation of the horizontal line that passes through the point (−2, −1). y = −1 y = −2 x = −2 x = −1

NNADVOKAT [17]

For a horizontal line, gradient is zero;
y=mx+c
since m=0
y=c
Replacing for y from given point;
-1=c
c=-1
y-1

6 0

4 years ago

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