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aleksley [76]
3 years ago
13

What is the range plss help

Mathematics
2 answers:
Delvig [45]3 years ago
7 0

Answer:

Range is 1<x because there are arrow pointing away

Step-by-step explanation:

Brainliest? Just need 2 more

JulsSmile [24]3 years ago
7 0
It’s is the first one 1
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What is 3/2y - 3 + 5/3z when y= 6 and z = 3
kirill [66]

Answer:

-2.195

Step-by-step explanation:

Substitute the given values of y and z to the equation

= 3/2y-3+5/3z

= 3/2(6) - 3 + 5/3(3)

= 3/12 - 3 + 5/9

In order to easily solve the equation, we change the fractions into decimals.

3/12 = 0.25

5/9 = 0.555

= 0.25 - 3 + 0.555

= - 2.195

7 0
2 years ago
Read 2 more answers
Angles A and B are complementary. What is mB if mA = 15°? A. 75° B. 90° C. 105° D. 165°
guajiro [1.7K]

Answer:

90

Step-by-step explanation:

3 0
3 years ago
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At a candy store, Erika bought 3 kilograms of cinnamon red hots and 1 kilogram of gummy bears for $21.00. Meanwhile, Irene bough
sattari [20]
Taking the difference of the both you can see that 2 kg of gummy bears would cost $18. So each kg of gummy bear is $9. Now subtract $9 from what Erika bought, and 3 kg of red hots are $12. So each kg of red hots are $4.
8 0
3 years ago
CONDITIONAL PROBABILITY ASSISTANCE
Mars2501 [29]

Consider such events:

A - selected student is freshmen

B - selected student is girl

A\cap B - selected student is freshman is girl

A|B - choosen girl is freshmen.

Use formula Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

From the table you can see that girls that are freshmen are 4 from all 30 people, then Pr(A\cap B)=\dfrac{4}{30}. There are 18 girls, then Pr(B)=\dfrac{18}{30}. Substitute into the formula:

Pr(A|B)=\dfrac{\frac{4}{30} }{\frac{18}{30} }=\dfrac{4}{18} =\dfrac{2}{9}.

Answer: Pr(A|B)=\dfrac{2}{9}.

4 0
4 years ago
Five percent of all vcrs manufactured by a large electronics company are defective. a quality control inspector randomly inspect
harkovskaia [24]
Binomial
Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n=10)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (defective/normal)3. Probability is known and remains constant throughout the trials (p=5%)4. All trials are random and independent of the others (assumed from context)The number of successes, x, is then given byP(x)=C(n,x)p^x(1-p)^{n-x}whereC(n,x)=\frac{n!}{x!(n-x)!}
Substituting values, p=0.05, n=10, X=exactly 1
for X=1 (defective out of n)
P(X=1)=C(10,1)0.05^1*(1-0.05)^(10-1)
=10!/(1!9!)*0.05*0.95^9
=10*0.05*0.0630249
=0.315125 (to 6 places of decimal)
7 0
3 years ago
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