x² - 4x - 12 = 0
Factor the left side: (x + 2) · (x - 6) = 0
The equation is true if either factor is zero.
If (x + 2) = 0 then x = -2 .
If (x - 6) = 0 then x = 6 .
Answer: (2,2)
Step-by-step explanation:
I'm going to use substitution to solve this:
First, I use the second equation to solve for y in terms of x.
2x - y = 2
-y = 2 - 2x
y = 2x - 2
Then, I plug the value for y into the first equation:
2x + 4y = 12
2x + 4(2x - 2) = 12
2x + 8x - 8 = 12
10x - 8 = 12
10x = 20
x = 2
Now that we have x, we can plug it into either equation (I used the first) to get the value for y:
2x + 4y = 12
2(2) + 4y = 12
4 + 4y = 12
4y = 8
y = 2
We get the point (2,2) as a solution.
Note: This is the point where both lines intersect.
I think its 15+y or 15y im not surw
