C=2pr, r=c/(2p)
a=pr^2, using r found above we get:
a=p(c^2/(4p^2))
a=(c^2)/(4p), since c=106.76 and we approximate pi as 3.14
a=(106.76^2)/(4*3.14)
a=11612.2176/12.56 cm^2
a≈924.54 cm^2 (to nearest one-hundredth of a square cm)
Answer:
32 students
Step-by-step explanation:
8 teams
32 students
(0,6),(4,10),(1,7), all you need to do is find a random y value and add 6 to it to get the x value.
Answer:
Step-by-step explanation:
We are looking for P(58 < x < 64). We need to find the percentage to the left of the z-scores for each of these numbers. To find the z scores, use the formula:

which gives us a z-score of -1. The percentage of numbers to the left of a z-score of -1 is .1586553
Now for the other z-score:
which gives us a z-score of .5. The percentage of numbers to the left of a z-score of .5 is .69146246
The lower percentage subtracted from the higher gives the area in question:
.69146246 - .1586553 = .53280716, or as a percentage, 53.3%, choice A.