Answer:
The t value for 99% CI for 21 df is 2.831.
The critical value that should be used in constructing the confidence interval is (64.593, 86.407).
Step-by-step explanation:
Now the sample size is less than 30 and also population standard deviation is not known.
Then we will use t distribution to find CI
t value for 99% CI for 21 df is TINV(0.01,21)=2.831
The margin of error is 
Hence CI is
100 pounds converted to kilograms is 45.3592
Answer:
-153.91
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The answer you are going to be looking for with this question is 16.4. Hope this helps you out a little :)