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3 years ago

Match each word with its definition

1 answer:

7 0

Answer: difference is subtraction. Quotient is division. Product is multiplication. Sum is addition and inverse operation is an operation that creates a reverse effect of another operation.

Step-by-step explanation:

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Can you guys help ?

kobusy [5.1K]

The answer is .52
glad 2 help

3 0

2 years ago

Need the a answer for this

FinnZ [79.3K]

Answer:

Given expression:

$\dfrac{14a^4b^6c^{-10}}{8a^{-2}b^3c^{-5}}$

Separate the variables:

$\implies \dfrac{14}{8} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}$

Reduce the first fraction:

$\implies \dfrac{7}{4} \cdot \dfrac{a^4}{a^{-2}} \cdot \dfrac{b^6}{b^3} \cdot \dfrac{c^{-10}}{c^{-5}}$

$\textsf{Apply Division Property of Exponents rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:$

$\implies \dfrac{7}{4} \cdot a^{4-(-2)} \cdot b^{6-3} \cdot c^{-10-(-5)}$

$\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot c^{-5}$

$\textsf{Apply Negative Property of Exponents rule} \quad a^{-n}=\dfrac{1}{a^n}$

$\implies \dfrac{7}{4} \cdot a^{6} \cdot b^{3} \cdot \dfrac{1}{c^5}$

Therefore:

$\implies \dfrac{7a^6b^3}{4c^5}$

4 0

1 year ago

A container of oregano is 17 pounds heavier than a container of peppercorns their total weight is 253 pounds the peppercorns wil

34kurt

Alright, we can turn the word problem at the beginning into an equation.
Let's represent oregano with "o" and peppercorns as "p".
o=p+17
Also, we know that the two added together are 253 pounds.
o+p=253
Since we know that o=p+17, let's substitute it into the second equation.
(p+17)+p=253
2p+17=253
-17 -17
2p=236
p=118
So, we have 118 pounds of peppercorns. (Although it's irrelevant to the second half of the equation, we also know we have 135 pounds of oregano)
Now, let's convert pounds to ounces.
1 pound = 16 ounces.
So, multiply 118 by 16....
118*16=1888
So, you can make 1888 one-ounce bags of peppercorns.

8 0

3 years ago

Read 2 more answers

2) An outdoor staircase has a total vertical elevation of 11 feet from the road level to the front entrance of a building. If th

LekaFEV [45]

2a

tan37=r/8

r=8tan37

r≈6 in rise per step (to nearest whole inch)

2b

11*12/6=22 steps needed to climb the 11 ft to the entrance

...

3a

tanα=14/20

α=arctan(7/10)

α≈35° (to nearest whole degree)

..

3b

tanα=21/17

α=arctan(21/17)

α≈51° (to nearest degree)

3 0

2 years ago

Someone please help answer this and explain what this is and how to solve this?

lisabon 2012 [21]

Answer:

easy it is 100 trust me

Step-by-step explanation:

3 0

2 years ago