A: b = 7:4

Explain how the graph of each given function is a transformation of the graph of y=x^2.

marysya [2.9K]

A. The function is bing translated down 5 units

b. The function is being stretched vertically stretched by 2 units

c. He function is being translated 5 units to the right

d. The functions being flipped and vertically stretched by 3 units

4 0

3 years ago

Jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?

mash [69]

jonas wants to mail a package that weighs 4.2 kilogram. how much dose the package weigh in pounds?

we know that

1 kg = 2.20462262185 lb

1 kg=2.2 lb

we have

4.2 kg

Convert to pounds

so

4.2 kg=4.2*(2.2)=9.24 pounds

therefore

the answer is 9.24 pounds

7 0

1 year ago

What are the zeros of this polynomial and state their multiplicity at each y=(x-5)(x+2)^2

N76 [4]

Answer:

C.

Step-by-step explanation:

The zeros of a polynomial are the x-intercepts of the function. To find them, we factor the polynomial and set each factor equal to 0.

This polynomial is already factored so set each to 0 and solve for x.

$x-5=0\\x=5\\(x+2)^{2}=0 \\(x+2)=0\\x=-2$

This means x=-2, 5. Each zero or root has a multiplicity - the number of times the factor occurs. This is also known as the exponent of the factor expression.

(x+5) occurs once since it has exponent 1.

$(x+2)^{2}$ occurs twoce since it has exponent 2.

x=5 mult. 1, x=-2 mult. 2

7 0

3 years ago

Find the expected value of the winnings from a game that has the following payout probability distribution: Skip Payout ($) 1 2

Nezavi [6.7K]

Answer:

$4.35

Step-by-step explanation:

The expected value of a random variable X, often denoted as E(X), indicates the probability-weighted average of all possible values/events. The general formula of expected value is

$\mathrm{E(\textit X \mathrm)} = \displaystyle\sum_{\mathclap{i=1}}^{k} \ X \times P(X) \\ \\ \\ = X_{1} \times P(X_{1}) \ + \ X_{2} \times P(X_{2}) \ + \ X_{3} \times P(X_{3}) + \ \cdots \ + X_{k} \times P(X_{k})$ .

Therefore, the expected value of the winnings from a game is

$\mathrm{E(\textit X \mathrm)} \ = \ 1 \times 0.35 \ + \ 2 \times 0.2 \ + \ 5 \times 0.1 + \ 8 \times 0.2 \ + 10 \times 0.15 \\ \\ = \ 4.35 \ \ (\mathrm{nearest \ hundredth})$ .