Answer:
Distance from the base of the cliff to the point on the ground = 7608 feet
Step-by-step explanation:
Given: Height of the cliff is 532 feet, angle of depression from the top of the cliff to a point on the ground is equal to 4 degrees.
To find: distance from the base of the cliff to the point on the ground
Solution:
In ΔABC,
(Alternate interior angles)
For any angle 
, 
side opposite to angle/side adjacent to angle
Put 
Distance from the base of the cliff to the point on the ground = 7608 feet
Answer:
kkkkkkkk
Step-by-step explanation:
Answer:
public class MovieRental
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Enter the number of movie rentals: ");
int movieRentals = in.nextInt();
System.out.print("Enter the number of members referred to the video club: ");
int memberReferral = in.nextInt();
in.close();
double discountVal = Math.min(movieRentals + memberReferral, 75);
System.out.println("The discount is equal to: " + discountVal);
}
}
Answer:
The awnser is March 15th because every 12 days they are off at the same time
Step-by-step explanation:
<h2>
BRAINLIEST PLEASE</h2>
Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
