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3 years ago

Please help with this

Mathematics

1 answer:

Degger [83]3 years ago

3 0

All of them are wrong its 91 but if you want click or circle 90

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Vaselesa [24]

Answer:

y=4

Step-by-step explanation:

8 0

3 years ago

A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co

White raven [17]

Answer:

The value of x would be $\frac{3}{5}y$ or $\frac{3}{8}z$

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain 5% gravel mixture,

Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,

⇒ 0.1x + 0.02y = 0.05(x+y),

0.1x - 0.05x = 0.05y - 0.02y

0.05x = 0.03y

$\implies x = \frac{0.03}{0.05}y=\frac{3}{5}y----(1)$

Now, resultant mixture is z ton,

i.e. $z=x+y$

$\implies y = z - x$

From equation (1),

$x=\frac{3}{5}(z-x) = \frac{3}{5}z-\frac{3}{5}x$

$x+\frac{3}{5}x=\frac{3}{5}z$

$\frac{8}{5}x=\frac{3}{5}z$

$x=\frac{3}{8}z$

3 0

3 years ago

Solve the equation on the interval [0,2π). cos^4x=cos^4xcscx

Alisiya [41]

$\bf cos^4(x)=cos^4(x)csc(x)\\\\
-----------------------------\\\\
cos^4(x)=cos^4(x)\cfrac{1}{sin(x)}\implies cos^4(x)=\cfrac{cos^4(x)}{sin(x)}
\\\\\\
cos^4(x)sin(x)=cos^4(x)\implies cos^4(x)sin(x)-cos^4(x)=0
\\\\\\
cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
cos^4(x)=0\to x=cos^{-1}(0)\\
----------\\
sin(x)-1=0\\
sin(x)=1\to x=sin^{-1}(1)
\end{cases}$

$\bf \measuredangle x = cos^{-1}(0)\implies \measuredangle x = 
\begin{cases}
\frac{\pi }{2}\\\\
\frac{3\pi }{2}
\end{cases}
\\\\\\
\measuredangle x=sin^{-1}(1)\implies \measuredangle x=\frac{\pi }{2}$

3 0

3 years ago

Simplify this expression: cos t(sec t − cos t)

Nostrana [21]