Ask question

Ask question

All categories

3 years ago

8

The relationship between the base and rate a plumber charges and his hourly fee is modeled by the linear function f (x) = 25x +

100 where x is the number of hours he works. What is the total bill if the plumber works for 6 hours ?

1 answer:

marysya [2.9K]3 years ago

4 0

F(6)=25(6)+100
f(6)=150+100
f(6)=250
Final answer: $250

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%7B4%7D%5E%7B3%7D%20" id="TexFormula1" title=" {4}^{3} " alt=" {4}^{3} " align="absmiddle"

quester [9]

Answer:

64

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please I need your help

BlackZzzverrR [31]

Answer:

the volume would change since the object is heavier

Step-by-step explanation:

I can't see other steps and the more the mass and the area of the object the more volume ots take up

8 0

3 years ago

Read 2 more answers

A company boss is planning on ordering a gift for each of his employees. He takes a sample of 30 employees in the company and as

Otrada [13]

Answer:

I think the answer is 33

Step-by-step explanation:

Extremely sorry if it's wrong

6 0

2 years ago

Please help me I’m so stressed

djverab [1.8K]

This is just like the other problem. The coefficient infront of the b which is "2" is your constant of proportionality. It makes the relationship between the number of bulbs and flowers signaling that for every flower there has to be 2 bulbs.

4 0

3 years ago

Find the x-values that are solutions of the equation 5cot^2x-15=0

julia-pushkina [17]

First solve for the trig function 'cot'
$cot^2 x = \frac{15}{5} = 3$

Next take the sqrt of both sides (include plus/minus)
$cot x = \pm \sqrt{3}$

Now take reciprocal of both sides, this will change trig function to 'tan'
(cot = 1/tan)

$tan x = \pm \frac{1}{\sqrt{3}} = \pm \frac{\sqrt{3}}{3}$

Finally use the unit circle or inverse tan on your calculator to find x.
There will be 4 solutions, one for each quadrant.

$x = \frac{\pi}{6}, \frac{5\pi}{6}, \frac{7\pi}{6}, \frac{11\pi}{6}$

3 0

3 years ago