Find the domain and range!!! 10 points!! Help needed

Mathematics

1 answer:

larisa86 [58]4 years ago

4 0

ANSWER

B. Domain is (-∞,∞) and Range is (-∞,∞).

The given function is

$f(x) = \sqrt[3]{x - 6} + 5$

This is function is obtained by shifting the base cubic root function 6 units to the right and 5 units up.

This function is defined for all real values of x.

Therefore the domain is all real numbers.

The range is all real numbers.

The domain for this function becomes the range for the inverse function and the range becomes the domain.

Hence the domain is (-∞,∞) and the range is (-∞,∞).

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The correct answer is: [B]: "40 yd² " .
_____________________________________________________
First, find the area of the triangle:

The formula of the area of a triangle, "A":

A = (1/2) * b * h ;

in which: " A = area (in units 'squared') ; in our case, " yd² " ;

" b = base length" = 6 yd.

" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;

= " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:

The formula for the area, "A" of a square:

A = s² ;

in which: "A = area (in "units squared") ; in our case, " yd² " ;

"s = side length (since a 'square' has all FOUR (4) equal side lengths);

A = s² = (4 yd)² = 4² * yd² = "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
→ " 24 yd² + 16 yd² " ;

to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
_________________________________________________

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