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irakobra [83]
3 years ago
13

6th grade math :) ...

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer:

0.08.

0.09

Step-by-step explanation:

Arada [10]3 years ago
4 0

Answer:

Question 1) $0.08 per oz

Question 2) $0.09 per oz

Step-by-step explanation:

You have to divide the price by how many ounces there are.

$1.92 / 24 = $0.08

$1.35 / 15 = $0.09

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Number of weeks and amount of money in account chart
Contact [7]
The answer would be C.
3 0
3 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
Tim has a box of 15 markers. He gives 3 markers each to 4 friends. What expression can show the number of markers Tim has left?
Nina [5.8K]
15-(4x3) =3 , idk how to explain it but the answers 3 for sure
7 0
3 years ago
Read 2 more answers
The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a
dybincka [34]

Answer:

The equation 35x+93\frac{3}{4} =190 gives average time spent on 35 rehearsals.

Step-by-step explanation:

We are supposed to find that what question does the equation 35x+93\frac{3}{4} =190 finds answer of.

We can see that 35x represents time spent on 35 rehearsals and 93\frac{3}{4} is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

35x+\frac{375}{4} =190

After subtracting 93\frac{3}{4} hours from 190 hours we will get time spent on 35 rehearsals.

35x =190-\frac{375}{4}

35x =\frac{760-375}{4}

35x =\frac{385}{4}

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

x =\frac{96.25}{35}=2.75  

Therefore, equation 35x+93\frac{3}{4} =190 finds average time spent on 35 rehearsals.


7 0
3 years ago
Read 2 more answers
F(x)=−x 2−3x+3 find f(7)
lidiya [134]

Answer:

22

Step-by-step explanation:

because i swiched the x's to the 7 and multipled

4 0
2 years ago
Read 2 more answers
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