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Elden [556K]
3 years ago
14

Which property of addition is shown?

Mathematics
1 answer:
ikadub [295]3 years ago
7 0

Answer:

ASSOCIATIVE PROPERY

Step-by-step explanation:

You might be interested in
A. 5x - 2 = 8<br>b. 4x - 3= 2x + 9<br>C. 6x + 3 = 2x + 8​
Elena L [17]

Answer:

a) x=2

b)x=12

c)x=5/4

Step-by-step explanation:

a)5x-2=8

5x=8+2

5x=10

x=2

b)4x-3=2x+9

4x-2x=9+3

2x=12

x=6

c)6x+3=2x+8

6x-2x=8-3

4x=5

x=5/4

Proof:

a)5x-2=8

5(2)-2=8

10-2=8

8=8

b)4x-3=2x+9

4(12)-3=2(12)+9

48-3=24+9

45=45

c)6x+3=2x+8

6(5/4)+3=2(5/4)+8

30/4+3=10/4+8

15/2+3=5/2+8

10.5=10.5

Hope this helps ;) ❤❤❤

4 0
3 years ago
Anca a citit 375 de pagini dintr-o carte. În fiecare zi, începând cu a doua zi, ea a citit cu 5 pagini mai mult decât în ziua pr
prohojiy [21]

Answer:

a=65

Step-by-step explanation:

Avem 375 pagini

Notam cu a numaruide pagini

In prima zi avem-a, poi a doua zi-a+5, a treia-a+10, apatra-a+

15 si a cincea zi avem-a+20

Le adunam si egalam cu 375

5a=50=375

5a=325

a=65

8 0
4 years ago
Which of the following rational functions is graphed below?
Zepler [3.9K]

Answer:

  D.  F(x) = 1/(x +5)²

Step-by-step explanation:

The vertical asymptote at x=-5 tells you that x=-5 will be a zero of the denominator. The only equation with a denominator factor of (x+5) is ...

  F(x) = 1/(x +5)²

_____

<em>Additional comment</em>

The fact that the value of F(x) does not change sign at the vertical asymptote tells you the denominator factor will be of even degree. That is taken for granted here, as all denominators are squares in the answer choices.

3 0
2 years ago
Find the value of x if mPYA 12x 20 and m LPLA 110O 220O 240O 20O 40
romanna [79]
M<PLA = 1/2 m PYA
110 = 1/2 (12x - 20)
12x - 20 = 220
12x = 220 + 20 = 240
x = 240 / 12 = 20
4 0
4 years ago
"Solving Equations by Completing the Square: m^2+2m-48=-6
kvv77 [185]
m^2+2m-48=-6 \\ \\ m^2+2m-48+6=0\\ \\m^2+2m-42=0\\ \\a=1, \ b= 2, \ c= -42 \\ \\\Delta = b^{2}-4ac = 2^{2}-4*1*(-42)= 4+168 =172 \\\\\sqrt{\Delta }=\sqrt{172} =\sqrt{4*43}=2\sqrt{43}\\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-2-2\sqrt{43}}{2}=\frac{2(-1-\sqrt{43})}{2}= -1-\sqrt{43} \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} = \frac{-2+2\sqrt{43}}{2}=\frac{ 2(-1+\sqrt{43})}{2}= -1+\sqrt{43}
5 0
3 years ago
Read 2 more answers
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