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3 years ago

Which expression is equivalent to -3x(x-4)-2x(x+3)?

Mathematics

2 answers:

kvv77 [185]3 years ago

6 0

Answer

=5x²+12x-6

Step-by-step explanation:

you multiply -3x(x-4)-2x(x+3)

=-3x²+12x-2x²-6

group like terms

=-3x²-2x²+12x-6

=-5x²+12x-6

Ymorist [56]3 years ago

4 0

Answer:

x(x^2 + 6)

Step-by-step explanation:

We are to simplify -3x(x-4)-2x(x+3). Begin by performing the indicated multiplication. We get -3x^2 + 12x - 2x^2 - 6x.

Combining like terms, we get -5x^2 + 6x, which is equivalent to

x(x^2 + 6)

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Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t

hram777 [196]

Answer:

a. $\mu=15$

b. $\mu=7.8586 \ and \ \mu=22.1414$

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

$P(X=k)=C_k^n.p^k.(1-p)^{n-k}$

Let n be the number of trials, $n=100$

and p be the probability of success, $p=15\%$

The mean of a binomial distribution is the probability x sample size.

$\mu=np=100\times0.15=15$

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as: $\sigma=\sqrt npq\\q=1-p$

Therefore, $\sigma=\sqrt(100\times0.015\times0.85)=3.5707$

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

$sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414$

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c. $x=45$ is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0

3 years ago

If f(x)=ln(sin(2x)), f''(π/4) is equal to

Licemer1 [7]

Use the chain rule to compute the second derivative:

$f(x)=\ln(\sin(2x))$

The first derivative is

$f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}$

$f'(x)=2\cot(2x)$

Then the second derivative is

$f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'$

$f''(x)=-4\csc^2(2x)$

Then plug in π/4 for x :

$f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4$

4 0

3 years ago

A. Complete the table if y varies

serious [3.7K]

Direct variation is represented by the equation y = k × x and inverse variation is represented by y = k/x

Table 1:

y = k × x

30 = k × 5

30 = 5k

k = 30/5

k = 6

So,

y = 30

y = 30 k = 6

y = 30 k = 6x = 5

y = 30 k = 6x = 5Equation: y = 6x

y = k × x

y = 10 × 8

y = 80

So,

y = 80

y = 80 k = 10

y = 80 k = 10x = 8

y = 80 k = 10x = 8Equation: y = 10x

y = 3x

18 = 3x

x = 18/3

x = 6

So,

y = 18

y = 18k = 3

y = 18k = 3x = 6

y = 18k = 3x = 6Equation: y = 3x

y = 2x²

72 = 2x²

x² = 72/2

x² = 36

x = √36

x = 6

So,

y = 72

y = 72k = 2

y = 72k = 2x = 6

y = 72k = 2x = 6Equation: y = 2x²

Table 2:

y = k/x

5 = k/6

5 × 6 = k

30 = k

So,

y = 5

y = 5k = 30

y = 5k = 30x = 6

y = 5k = 30x = 6Equation: y = 30/x

y = k/x

y = 36/4

y = 9

So,

y = 9

y = 9k = 36

y = 9k = 36x = 4

y = 9k = 36x = 4Equation: y = 36/x

y = 60/x

20 = 60/x

20x = 60

x = 60/20

x = 3

So,

y = 20

y = 20k = 60

y = 20k = 60x = 3

y = 20k = 60x = 3Equation: y = 60/x

y = 24/x

y = 24/12

y = 2

So,

y = 2

y = 2k = 24

y = 2k = 24x = 12

y = 2k = 24x = 12Equation: y = 24/x

brainly.com/question/472621

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2 years ago

The cost for x number of students to attend an after school sporting event can be represented bu the functon C(x). If C(124) = 5

lara [203]

Alright! Given that C(x) is Cost(Students) = 558, we can eliminate:

2. 558 students paid to attend the event.
5. The event generated $124 from student revenue.

Now, in order to find the cost per student we simply divide 124 on both sides:

$\frac{C(124)}{124} = \frac{558}{124}$

124 cancels on the left and 558/124 is 4.5 or $4.50.

Since we just determined the cost of one student, we can eliminate 3.

To check if 124 students paid, we simply add the cost to the equation and check:

4.5(124) = 558

558 = 558 √

It checks out, so we determined that both 1 and 4 are correct.

7 0

3 years ago

The relationship between altitude and the boiling point of a liquid is linear. At sea level, the liquid boils at 220°F. As the

Kipish [7]

Answer:

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Step-by-step explanation:

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3 years ago