Let us say T= probability of head turning up = 1/2 in one toss
H = probability of a tail turning up = 1/2 in one toss
Then P (56 heads or more) =
1/2^100 [ C(100,56) + C(100,57) + C(100,58) + ....
C(100,98) + C(100,99) + C(100,100) ]
where C(N, R) = N ! / [ (N - R)! R! ] number of occurrances of R formed from
N tosses.
Answer:
30 students
Step-by-step explanation:
3 students = 10% of the class.
x students = 90% of the class.
(If more, less divides. Let x be the subject. Since we know 10% of the class already, we have to find the remaining 90% that is 100% - 10% = 90%.)
x = 90%/ 10% × 3 students. ( the percentage signs cancel out and so do the zero's.)
x= 9/1 × 3 students ( 9/1 is the same as 9)
x= 27 students
(To find the total, you must add the 10% of the students to the remaining 90% of the students in the class.)
Total number of students in the class = 27 students + 3 students
= 30 students
hay numero pares e impares que son enteros y los pares son tosodo los que se pueden dividir entre dos siempre y cuando de numeros enteros
