Evaluate the expression for = −3 and = 5. r^{-4} s^2

Mathematics

2 answers:

Zanzabum3 years ago

6 0

If r = -3 and s = 5:
(r^-4)(s^2) = (-3^-4)(5^2) = (1/81)(25) = 25/81

Butoxors [25]3 years ago

5 0

If r = -3 and s = 5:
(r^-4)(s^2) = (-3^-4)(5^2) = (1/81)(25) = 25/81

If r = 5 and s = -3:
(r^-4)(s^2) = (5^-4)(3^2) = (1/625)(9) = 9/625

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1 year ago

What's the midpoint of a line segment joining the points (5, –4) and (–13, 12)?

Vikki [24]

Answer:

The midpoint of the line segment is located at (-4, 4).

Step-by-step explanation:

We're given the coordinate points of a line that can help us find the midpoint.

The midpoint formula for a line is written as:

$\bullet \ \ \ \displaystyle\big(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\big)$

Additionally, we are given the coordinate points (5, -4) and (-13, 12). We can use these and label them with the (x, y) system so we can substitute them into the formula.

In math, a coordinate pair is written as (x, y). This is where cos = x and sin = y. If we are given two coordinate pairs, we can label them with the (x, y) system but also incorporating a subscript to distinguish the two x-values from each other as well as the y-values. We do this by turning the two x-values into x₁ and x₂ and the y-values follow the same protocol: y₁ and y₂.

Therefore, we can label our two coordinates:

(5, -4)

x₁ = 5
y₁ = -4

(-13, 12)

x₂ = -13
y₂ = 12

Now, we can place these values into the midpoint formula and simplify to find our midpoint.

Recall that the midpoint formula is:

$\bullet \ \ \ \displaystyle\big(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\big)$

Therefore, let's substitute these values.

$\displaystyle\big(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\big)\\\\\\\big(\frac{5 + (-13)}{2}, \frac{(-4)+12}{2}\big)\\\\\\\big(\frac{-8}{2}, \frac{8}{2}\big)\\\\\\\boxed{(-4, 4)}$