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levacccp [35]
3 years ago
9

Need answers fast pleasee :(

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0
Letter c cuz hope this helped
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The sides of a quadrilateral whose sides are 85cm 143cm 165cm and 85cm and one of the diagonals is 154cm
yaroslaw [1]

Answer:85cm is kept comstant for a while

Step-by-step explanation:

For 2nd part

1m 80 cm

=1×100cm+ 80 cm

=100cm+ 80 cm

=180cm

So

#According to question,

If both are added then,

=85cm+180 cm

=265cm

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Step-by-step explanation:

7 0
4 years ago
Answer this Q QUIQLY PLZ
MariettaO [177]

Answer: 3. HAVE AN AMAZING DAY

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3 years ago
What is a Subset(It should be in the simplest form)
NISA [10]

Answer:

1 : a set each of whose elements is an element of an inclusive set. 2 : division, portion a subset of our community.

Step-by-step explanation:

In mathematics, set A is a subset of a set B if all elements of A are also elements of B; B is then a superset of A. It is possible for A and B to be equal; if they are unequal, then A is a proper subset of B. The relationship of one set being a subset of another is called inclusion

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8 0
2 years ago
Add the product of 5 and 6 with the product of 3 and 7
xz_007 [3.2K]

It is 51.                                           

5x6=30

3x7=21

30+21=51

Hope that I was of help.

5 0
3 years ago
Read 2 more answers
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
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