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Irina18 [472]
3 years ago
11

Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2​

Mathematics
1 answer:
Temka [501]3 years ago
5 0

Answer:

-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

a_n=a_1+(n-1)d

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

a_1=-10\\d=-2

substitute

a_n=-10+(n-1)(-2)

a_n=-10-2n+2

a_n=-2n-8

so

<u><em>Find the first ten terms</em></u>

a_1=-10

For n=2 ----> a_2=-2(2)-8=-12

For n=3 ----> a_3=-2(3)-8=-14

For n=4 ----> a_4=-2(4)-8=-16

For n=5 ----> a_5=-2(5)-8=-18

For n=6 ----> a_6=-2(6)-8=-20

For n=7 ----> a_7=-2(7)-8=-22

For n=8 ----> a_8=-2(8)-8=-24

For n=9 ----> a_9=-2(9)-8=-26

For n=10 ----> a_1_0=-2(10)-8=-28

The sequence is

-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...

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<h3>Riemann sum</h3>

When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

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__

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

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