The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
4
Step-by-step explanation:
Gradient is the same as slope to get your answer follow this formula y2 - y1 divided x2 -x1 in this problem it will look like this
4 - (-4) /1 - (-1) =
8 / 2 =
= 4
I hope this helps!!
Answer:
<h3>
±√1.69 = +1.3 and -1.3</h3>
Step-by-step explanation:
√169 = 13
square root and two digits after dot means the result need to has one digit after dot (number of digits after dot divided by 2 because of square root)
so √1.69 = 1.3
Answer:
.
Step-by-step explanation:
I think it’s about 4.3 mph