Good evening ,
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Answer:
1) (f+g)(1) = e
2) (fg)(1) = 0
3) (3f)(1) = 3e
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Step-by-step explanation:
1) (f+g)(1) = f(1) + g(1) = e¹ + log1 = e + 0 = e.
2) (fg)(1) = f(1) × g(1) = e¹ × log(1) = e¹ × 0 = e × 0 = 0.
3) (3f)(1) = 3×f(1) = 3×e¹ = 3e.
:)
Swap x and y's positions
f(x) is another way of saying y, so basically tha initial function is y = 1-2x^3.
Change it up to x = 1-2y^3 and solve for y
X - 1 = - 2y^3
(X - 1)/-2 = y^3
So the cube root of ((x-1)/2) = y
- 3 + 3x = 2x – 13
Bring -3 to the right side of the equation by adding 3 to both sides
(- 3 + 3) + 3x = 2x – 13 + 3
0 + 3x = 2x - 10
3x = 2x - 10
Bring 2x to the other side by subtracting 2x to both sides
3x - 2x = 2x - 2x - 10
x = -10
Check:
-3 + 3(-10) = 2(-10) - 13
-3 + (-30) = -20 - 13
-33 = -33
Hope this helped!
~Just a girl in love with Shawn Mendes
Answer:
30?
Step-by-step explanation:
divide 20 by 8 and then times the answer by 12
I don't really get this question but simply put, if you are in college syntax matters very much. (13-4) = 9 *(x-5) = 9x-45.. although in this case. since there isn't a bracket around 13-4. you'd multiply by the -4 first, giving you, 4x-20+30 =4x-10
