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2 years ago

11

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

1 answer:

DiKsa [7]2 years ago

4 0

Answer:

12

Hope it helps

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What is the answer 2.07 ÷ 0.9

storchak [24]

The answer is 2.3 right.

5 0

2 years ago

Please answer this like I

White raven [17]

roses are red violets are blue my heart is dead im such a fool

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3 years ago

Marine biologists have determined that when a shark detectsthe presence of blood in the water, it will swim in the directionin w

siniylev [52]

Solution :

a). The level curves of the function :

$C(x,y) = e^{-(x^2+2y^2)/10^4}$

are actually the curves

$e^{-(x^2+2y^2)/10^4}=k$

where k is a positive constant.

The equation is equivalent to

$x^2+2y^2=K$

$\Rightarrow \frac{x^2}{(\sqrt K)^2}+\frac{y^2}{(\sqrt {K/2})^2}=1, \text{ where}\ K = -10^4 \ln k$

which is a family of ellipses.

We sketch the level curves for K =1,2,3 and 4.

If the shark always swim in the direction of maximum increase of blood concentration, its direction at any point would coincide with the gradient vector.

Then we know the shark's path is perpendicular to the level curves it intersects.

b). We have :

$\triangledown C= \frac{\partial C}{\partial x}i+\frac{\partial C}{\partial y}j$

$\Rightarrow \triangledown C =-\frac{2}{10^4}e^{-(x^2+2y^2)/10^4}(xi+2yj),$ and

$\triangledown C$ points in the direction of most rapid increase in concentration, which means $\triangledown C$ is tangent to the most rapid increase curve.

$r(t)=x(t)i+y(t)j$ is a parametrization of the most $\text{rapid increase curve}$ , then

$\frac{dx}{dt}=\frac{dx}{dt}i+\frac{dy}{dt}j$ is a tangent to the curve.

So then we have that $\frac{dr}{dt}=\lambda \triangledown C$

$\Rightarrow \frac{dx}{dt}=-\frac{2\lambda x}{10^4}e^{-(x^2+2y^2)/10^4}, \frac{dy}{dt}=-\frac{4\lambda y}{10^4}e^{-(x^2+2y^2)/10^4}$

∴ $\frac{dy}{dx}=\frac{dy/dt}{dx/dt}=\frac{2y}{x}$

Using separation of variables,

$\frac{dy}{y}=2\frac{dx}{x}$

$\int\frac{dy}{y}=2\int \frac{dx}{x}$

$\ln y=2 \ln x$

⇒ y = kx^2 for some constant k

but we know that $y(x_0)=y_0$

$\Rightarrow kx_0^2=y_0$

$\Rightarrow k =\frac{y_0}{x_0^2}$

∴ The path of the shark will follow is along the parabola

$y=\frac{y_0}{x_0^2}x^2$

$y=y_0\left(\frac{x}{x_0}\right)^2$

7 0

2 years ago

Can someone please help me with this

krek1111 [17]

Step-by-step explanation:

0.1 repeating is 1/9, so the number is 4 1/9.

5 0

3 years ago

Solve the system graphically<br> 1. x-2y=6 and 3x+2y=-6<br><br> 2. x-y=0 and 2x+3y=-5

zysi [14]

Step-by-step explanation:

1)The given equations are:

x − 2y = 6 ...(i)

3x − 6y = 0 ...(ii)

Putting x = 0 in equation (i) we get

=> 0 - 2y = 6

=> y = -3

x = 0, y = -3

Putting y = 0 in equation (i) we get

⇒x-2×0=6

⇒x=6

x = 6, y = 0

Use the following table to draw the graph

x 0 6

y -3 0

Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn

Graph of the equation ..(ii)

3x - 6y = 0 ...(ii)

Putting x = 0 in equation (ii) we get

⇒3×0-6y=0

=> y = 0

x = 0, y = 0

Putting x = 2 in equation (2) we get

⇒3×2-6y=0

=> y = 1

x = 2, y = 1

Use the following table to draw the graph.

x 0 2

y 0 1

Draw the graph by plotting the two points O(0,0) and D(2,1) from table

We see that the two lines are parallel, so they won’t intersect

Hence there is no solution

2)

3 0

2 years ago