This is just what my book says ;-; (Write a measurment division story problem for 6 divided by 3/4

Twice the sum of two numbers is 24. if one number is 2 times larger than the other, what is the smaller of the two numbers?

Vikki [24]

2(x+y)=24
2x=y

Use substitution. If y=2x, than we can substitute 2x for it in the other equation, because x and y equal the same things in both equations.

So using that we get 2(x+2x)=24

SIMPLIFY
2(3x)=24

DISTRIBUTE
6x=24.

DIVIDE: x=4.

If we substitute x into the original equations we get x=4 and y=8. Those are your two numbers.

Have a nice day! :)

4 0

3 years ago

Please help!!

Rama09 [41]

The associative property of addition is pretty much just any numbers in place of these: a + (b + c) = (a + b) + c. Therefore, your answer would be d) (6 + 1) + 9 = 6 + (1 + 9)

6 0

3 years ago

Multiply me by 4 then subtract 13 if you divide me by 3 and add 17 you get 22

8_murik_8 [283]

You have to do the opposite

22-17=5
5x3=15
15+13=28
28/4=7

The answer is 7. You can check this by doing what it says and if it makes 22, it’s correct. (I’ve already checked it) :)

6 0

3 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago

HELP RIGHT NOW PIZZZ = FASTEST ANSWER BRAINLIEST AND I WILL THANK U

Nuetrik [128]

Answer:

1) The slope of the function $g(x)$ is $0$ and the slope of the function $f(x)$ is $-1$ .

2) The negative slope of the function $f(x)$ shows that it is the line is increasing and the slope $0$ of the function $g(x)$ shows that the line will always have the same y-coordinate.

3) The slope of the function is $f(x)$ is greater than the slope of the function $g(x)$ .

Step-by-step explanation:

For this exercise you need to know that the slope of any horizontal line is zero ( $m=0$ )

The slope of a line can be found with the following formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

You can observe in the graph of the function $g(x)$ given in the exercise, that this is an horizontal line. Then, you can conclude that its slope is:

$m=0$

The steps to find the slope of the function $f(x)$ shown in the table attached, are the following:

- Choose two points, from the table:

$(0,3)$ and $(4,-1)$

- You can say that:

$y_2=-1\\y_1=3\\\\x_2=4\\x_1=0$

- Substitute values into the formula $m=\frac{y_2-y_1}{x_2-x_1}$ :

$m=\frac{-1-3}{4-0}$

- Finally, evaluating, you get:

$m=\frac{-4}{4}\\\\m=-1$

Therefore:

1) The slope of the function $g(x)$ is $0$ and the slope of the function $f(x)$ is $-1$ .

2) The negative slope of the function $f(x)$ shows that it is the line is increasing and the slope $0$ of the function $g(x)$ shows that the line will always have the same y-coordinate.

3) The slope of the function is $f(x)$ is greater than the slope of the function $g(x)$ .

8 0

3 years ago