f(n) = f(n+1) +3
f(1) = f(2) +3
f(2) =f(3) +3
f(3) = f(4) +3
So f(1) = f(n) + 3* (n-1)
Put n=4 here so you found
f(1) = f(4) + 3* 3
= 22 +9
=31 ans
hope it helps
You can take the a out of both values. There are no other factorable parts of this expression. Your factored version would look something like this- a(5a-4b)
Hope that helped you out a bit nuzhat! ☺️
1. discriminant = b^2 - 4ac = (-5)^2 - (4 x 1 x 7) = 25 - 28 = -3 [imaginary root]
2. discriminant = (-5)^2 - (4 x 1 x -4) = 25 - (-16) = 25 + 16 = 41 [real and irrational root]
3. discriminant = (8)^2 - (4 x 16 x 1) = 64 - 64 = 0 [double root]
Read more on Brainly.com - brainly.com/question/1698047#readmore
hope it helps
